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GCSE/Biology/OCR

B1Cell-level systems — eukaryotic/prokaryotic cells, microscopy, mitosis, transport across membranes (diffusion, osmosis, active transport)

Notes

B1 Cell-level systems — OCR Gateway Biology (J257/01)

Eukaryotic vs Prokaryotic cells

All living cells are either eukaryotic or prokaryotic. Eukaryotic cells (animals, plants, fungi, protists) have a nucleus containing DNA enclosed in a nuclear membrane, plus membrane-bound organelles. Prokaryotic cells (bacteria) have no nucleus — DNA floats freely in the cytoplasm as a single circular chromosome, often supplemented by small rings of DNA called plasmids.

FeatureEukaryotic (animal)Eukaryotic (plant)Prokaryotic (bacterium)
Nucleus✗ (free DNA)
Cell wall✓ (cellulose)✓ (peptidoglycan)
Chloroplasts
Mitochondria
PlasmidsOften present
RibosomesLarge (80S)Large (80S)Small (70S)
Typical size10–100 µm10–100 µm1–10 µm

Key organelles — animal cell:

  • Nucleus — contains chromosomal DNA; controls cell activities.
  • Mitochondria — site of aerobic respiration; produce ATP.
  • Ribosomes — site of protein synthesis (translation).
  • Cell membrane — phospholipid bilayer; controls entry/exit of substances.
  • Cytoplasm — jelly-like fluid where metabolic reactions occur.

Additional plant-cell features:

  • Cell wall (cellulose) — gives structural support; freely permeable.
  • Chloroplasts — site of photosynthesis; contain chlorophyll.
  • Vacuole — large, permanent; maintains turgor pressure using cell sap.

Microscopy — PAG B1.1

OCR Gateway assesses microscopy in dedicated PAG questions (J257/01, Section A). Key skills:

Calculating magnification:

Magnification = Image size ÷ Actual size

Always check units are consistent (convert to µm or mm before dividing).

Calculating actual size:

Actual size = Image size ÷ Magnification

Example (common exam question): A cell appears 30 mm long under a ×600 microscope. What is the actual size? Actual size = 30 mm ÷ 600 = 0.05 mm = 50 µm.

Light vs electron microscope:

Light microscopeElectron microscope
Maximum magnification~×1500×500,000+
Resolution~200 nm~0.1 nm
Living specimensYesNo (must be fixed/stained)
Colour imagesYesNo (false colour added)
Subcellular structures visibleNucleus, chloroplasts, vacuoleMitochondria cristae, ribosomes, ER

Preparing a slide (PAG B1.1):

  1. Place material on slide; add a drop of water.
  2. Lower coverslip at 45° to exclude air bubbles.
  3. Apply iodine stain (plant cells) or methylene blue (animal cells) to improve contrast.
  4. Observe under low power first; focus with coarse adjustment; switch to high power and use fine adjustment.

Mitosis

Mitosis produces two genetically identical daughter cells. It is used for growth, repair, and asexual reproduction.

Stages (PMAT mnemonic):

  1. Prophase — chromosomes condense and become visible; nuclear envelope breaks down; spindle fibres form.
  2. Metaphase — chromosomes line up at the cell equator (metaphase plate); spindle fibres attach to centromeres.
  3. Anaphase — spindle fibres contract; sister chromatids separate and are pulled to opposite poles.
  4. Telophase — nuclear envelopes re-form around each set of chromosomes; chromosomes decondense.
  5. Cytokinesis — cytoplasm divides; two genetically identical daughter cells produced.

Human body cells are diploid (2n = 46). Each daughter cell receives the same 46 chromosomes.

Cancer is uncontrolled mitosis caused by mutations in genes that regulate the cell cycle (tumour suppressor genes and proto-oncogenes). OCR Gateway links this to B6 (disease).

Transport across membranes

The cell membrane is a selectively permeable phospholipid bilayer. Three transport mechanisms:

Diffusion

  • Movement of molecules from high → low concentration (down the concentration gradient).
  • Passive (no energy / ATP required).
  • Factors increasing rate: larger concentration gradient, higher temperature, smaller molecules, thinner membrane, larger surface area.
  • Examples: oxygen into respiring cells; CO₂ out of cells; urea into kidney tubule.

Osmosis

  • Specific case of diffusion — movement of water molecules from dilute solution (high water potential) → concentrated solution (low water potential) through a selectively permeable membrane.
  • If a cell is placed in:
    • Hypotonic (dilute) solution → water enters → cell swells (animal cell may burst = lysis; plant cell becomes turgid).
    • Hypertonic (concentrated) solution → water leaves → animal cell shrinks (crenation); plant cell becomes plasmolysed.

PAG B1.2 — Investigating osmosis in plant tissue: Cut cylinders of potato; measure mass before/after placing in sucrose solutions of varying concentration (0–1.0 mol/dm³). Plot % change in mass vs concentration. The point where mass = 0% change gives the concentration of cell sap (≈ 0.3 mol/dm³ for potato).

Active transport

  • Movement of molecules against the concentration gradient (low → high concentration).
  • Requires ATP (produced by respiration) and specific carrier proteins.
  • Examples: absorption of mineral ions (nitrates) by root hair cells; glucose absorption in the small intestine when concentration in blood > gut lumen.

Common OCR examiner traps

  1. Osmosis is only water — never say "glucose moves by osmosis."
  2. Active transport needs carrier proteins AND ATP — candidates often omit one.
  3. Magnification calculation units — always check both measurements use the same unit.
  4. Mitosis produces 2 cells; meiosis produces 4 — don't confuse them.
  5. Prokaryotes have no nucleus but DO have ribosomes (small 70S type).

AI-generated · claude-opus-4-7 · v3-ocr-biology

Practice questions

Try each before peeking at the worked solution.

  1. Question 17 marks

    Cell structure comparison

    OCR J257/01 — Short answer

    The diagram shows two cells, P (animal) and Q (bacterium).

    (a) Name two structures found in cell P that are not found in cell Q. [2 marks]

    (b) Cell Q has a diameter of approximately 2 µm. A student views it under a microscope and measures the image as 12 mm across. Calculate the magnification used. Show your working and give the correct unit. [3 marks]

    (c) Explain why a light microscope cannot be used to see ribosomes inside a bacterial cell. [2 marks]

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  2. Question 210 marks

    Osmosis investigation — PAG B1.2

    OCR J257/01 — PAG question

    A student investigates osmosis in potato tissue. She cuts 5 cylinders of equal size and places each in a different sucrose solution for 24 hours, then measures the % change in mass.

    Sucrose concentration (mol/dm³)% change in mass
    0.0+12
    0.2+5
    0.40
    0.6−7
    0.8−15

    (a) Plot the results on a graph (axes described). Draw the line of best fit. [3 marks]

    (b) Use the graph to estimate the concentration of the potato cell sap. Explain your reasoning. [2 marks]

    (c) Explain, using the concept of water potential, why the cylinders in 0.0 mol/dm³ gained mass. [3 marks]

    (d) Suggest one control variable in this investigation and explain why it must be kept constant. [2 marks]

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  3. Question 36 marks

    Stages of mitosis

    OCR J257/01 — Extended response

    Describe the events that occur during mitosis, from the start of prophase to the end of cytokinesis. You should refer to the behaviour of chromosomes at each stage. [6 marks]

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  4. Question 47 marks

    Diffusion vs active transport

    OCR J257/01 — Short answer

    Root hair cells absorb nitrate ions from the soil. The concentration of nitrate ions in the soil is lower than inside the root hair cell.

    (a) Name the process by which nitrate ions are absorbed. [1 mark]

    (b) Explain why this process requires mitochondria to be present in large numbers in root hair cells. [3 marks]

    (c) A student says: "If a plant is kept in waterlogged (anaerobic) soil, it will take up fewer nitrate ions." Evaluate this statement. [3 marks]

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  5. Question 54 marks

    Prokaryote vs eukaryote — multiple choice style

    OCR J257/01 — Section A (multiple choice / short)

    (a) Which of the following is found in a prokaryotic cell but NOT in an eukaryotic cell? [1 mark]
    A Large (80S) ribosomes
    B Plasmids
    C Mitochondria
    D Nucleus

    (b) A bacterium has a circular chromosome 4.6 × 10⁶ base pairs long. It also contains 3 plasmids, each 5000 base pairs long. How many base pairs of DNA does this bacterium contain in total? [2 marks]

    (c) Give one reason why bacteria can reproduce faster than eukaryotic cells. [1 mark]

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Flashcards

B1 — Cell-level systems — eukaryotic/prokaryotic cells, microscopy, mitosis, transport across membranes

10-card SR deck for OCR Biology topic B1

10 cards · spaced repetition (SM-2)