TopMyGrade

GCSE/Chemistry/Edexcel

CC7Rates of reaction — collision theory, factors, catalysts, exo/endothermic

Notes

Rates of reaction

Collision theory

A chemical reaction occurs when reactant particles collide with sufficient energy (at least the activation energy) and with the correct orientation. The rate of reaction is the amount of product formed (or reactant used) per unit time.

rate = change in amount ÷ time (in mol/s, g/s, or cm³/s)

Factors that increase the rate of reaction all work by increasing the frequency of successful collisions and/or lowering the activation energy:

FactorEffect on rateExplanation
Increase temperatureIncreases rateParticles have more kinetic energy → more frequent collisions AND higher proportion of collisions exceed Eₐ
Increase concentrationIncreases rateMore particles per unit volume → more frequent collisions
Increase pressure (gases)Increases rateSame as concentration — particles closer together
Increase surface areaIncreases rateMore particles exposed at surface → more collision opportunities
Add catalystIncreases rateProvides alternative reaction pathway with lower activation energy

Edexcel Core Practical CP4 — Rate of reaction (HCl + Mg or marble chips)

HCl + Mg ribbon: Mg + 2HCl → MgCl₂ + H₂↑ Measure: volume of H₂ gas collected in a gas syringe vs time. Plot a graph: rate = gradient of tangent to the curve.

HCl + marble chips (CaCO₃): CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂↑ Measure: mass loss (CO₂ escapes) vs time on a balance, or volume of CO₂ in gas syringe.

Variables investigated: temperature (use water baths), concentration of HCl, surface area of marble (powdered vs lumps), catalysts.

Interpreting graphs: a steeper initial gradient = faster rate; curve levels off when a reactant is used up.

Catalysts

A catalyst is a substance that increases the rate of reaction by providing an alternative reaction pathway with a lower activation energy. It is not consumed — it remains chemically unchanged at the end of the reaction (though it may be physically changed).

Homogeneous catalyst: in the same phase as the reactants (e.g. enzymes in biological reactions, H₂SO₄ catalyst in ester formation). Heterogeneous catalyst: in a different phase (e.g. solid Fe catalyst in the Haber process; Pt/Pd in catalytic converters).

Energy profile diagram: for a catalysed reaction, the activation energy peak is lower. The overall ΔH (enthalpy change) is the same — a catalyst does NOT change the thermodynamics.

Exothermic and endothermic reactions

Exothermic: energy is released to the surroundings. ΔH is negative. Temperature of surroundings increases. Examples: combustion, respiration, neutralisation, oxidation reactions.

Endothermic: energy is absorbed from the surroundings. ΔH is positive. Temperature of surroundings decreases. Examples: thermal decomposition, photosynthesis, dissolving ammonium nitrate in water.

Bond energy calculations (Higher)

Bond breaking requires energy (endothermic); bond forming releases energy (exothermic). ΔH = energy in (bonds broken) − energy out (bonds formed)

If ΔH < 0 (negative): exothermic (more energy released than absorbed). If ΔH > 0 (positive): endothermic (more energy absorbed than released).

Common mistakes

  1. Catalyst and equilibrium: a catalyst does not change the position of equilibrium — it only speeds up reaching it.
  2. Rate vs yield: rate and yield are different. High temperature increases rate but may decrease yield (for exothermic reactions at equilibrium).
  3. Surface area misconception: smaller particle size = larger surface area = faster rate. Powdered marble reacts faster than lumps.
  4. Energy profile: the catalyst lowers Eₐ, but ΔH (difference between reactant and product energy) is unchanged.
  5. Bond energy sign: always positive for bond-breaking; total ΔH can be negative or positive.

AI-generated · claude-opus-4-7 · v3-edexcel-chemistry

Practice questions

Try each before peeking at the worked solution.

  1. Question 18 marks

    Rates — collision theory explanation

    Edexcel Paper 2

    A student investigates the rate of reaction between marble chips (CaCO₃) and dilute hydrochloric acid by measuring the loss in mass over time.

    (a) Write a balanced equation for this reaction. (2 marks)
    (b) Explain, using collision theory, why increasing the temperature increases the rate of reaction. (3 marks)
    (c) The student also compares powdered marble with lumps of marble. Which produces a faster initial rate? Explain using collision theory. (3 marks)

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-edexcel-chemistry

  2. Question 26 marks

    Interpreting a rate graph — CP4

    Edexcel Paper 2 — Core Practical CP4

    A student plots a graph of volume of gas produced (cm³) against time (s) for two experiments:

    • Experiment A: 50 cm³ of 1 mol/dm³ HCl + excess Mg
    • Experiment B: 50 cm³ of 2 mol/dm³ HCl + excess Mg

    (a) Which experiment (A or B) produces a steeper initial gradient? Give a reason. (2 marks)
    (b) Both experiments produce the same final volume of gas. Explain why. (2 marks)
    (c) A student says: "If I add a catalyst, more gas will be produced." Is this correct? Explain. (2 marks)

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-edexcel-chemistry

  3. Question 36 marks

    Exothermic and endothermic — energy profiles

    Edexcel Paper 2

    The diagram shows an energy profile for a reaction (described in words below):

    • Reactants are at a higher energy level than products.
    • There is an energy peak between reactants and products.

    (a) Is this reaction exothermic or endothermic? Give a reason. (2 marks)
    (b) Label on the diagram: activation energy (Eₐ) and overall energy change (ΔH). (2 marks)
    (c) A catalyst is added. Describe how this changes the energy profile. (2 marks)

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-edexcel-chemistry

  4. Question 45 marks

    Bond energy calculation

    Edexcel Paper 2 — Higher

    Use the bond energies below to calculate the enthalpy change for the reaction:
    H₂ + Cl₂ → 2HCl

    Bond energies: H−H = 436 kJ/mol; Cl−Cl = 243 kJ/mol; H−Cl = 432 kJ/mol

    (a) Calculate the total energy required to break all bonds in the reactants. (2 marks)
    (b) Calculate the total energy released when all bonds form in the products. (1 mark)
    (c) Calculate the overall enthalpy change (ΔH) for the reaction. State whether it is exothermic or endothermic. (2 marks)

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-edexcel-chemistry

Flashcards

CC7 — Rates of reaction — collision theory, factors, catalysts, exo/endothermic

8-card SR deck for Edexcel Chemistry topic CC7

8 cards · spaced repetition (SM-2)