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GCSE/Combined Science/Edexcel

CP2.2Newton’s laws: 1st (inertia), 2nd (F = ma), 3rd (action–reaction); examples in lifts, vehicles

Notes

Newton's laws of motion and F = ma

Newton's First Law (inertia)

An object will remain at rest or continue to move at a constant velocity unless acted upon by a resultant (net) force.

  • Resultant force = 0: constant velocity (or stationary). Forces are balanced.
  • Resultant force ≠ 0: the object accelerates (changes speed or direction).

Inertia is the tendency of an object to resist changes to its motion. Mass is a measure of inertia — a larger mass needs a larger force to produce the same change in motion.

Newton's Second Law (F = ma)

The resultant force on an object equals the product of its mass and acceleration.

$$F = ma$$

Where:

  • F = resultant force (N)
  • m = mass (kg)
  • a = acceleration (m/s²)

Rearrangements:

  • a = F/m
  • m = F/a

Example: A 1200 kg car experiences a resultant force of 3600 N. Calculate its acceleration. a = F/m = 3600 / 1200 = 3 m/s².

Key points:

  • F is the resultant (net) force, not just one force.
  • If multiple forces act, find the resultant first (add if same direction, subtract if opposite).
  • Weight (W = mg) is a force caused by gravity. g ≈ 10 N/kg (or m/s²).

Newton's Third Law (action-reaction)

When object A exerts a force on object B, object B exerts an equal and opposite force on object A.

Key features of Newton's 3rd law pairs:

  • Equal in magnitude
  • Opposite in direction
  • Same type of force (e.g. both gravitational, both contact)
  • Act on DIFFERENT objects

Example: A person pushes a wall with 50 N → the wall pushes the person back with 50 N in the opposite direction.

Common misconception: "If forces are equal and opposite, why does anything accelerate?" The forces act on DIFFERENT objects — they do not cancel out for the same object.

Free-body diagrams

A free-body diagram shows all the forces acting ON a single object (not forces the object exerts on others). Forces are represented as arrows from the centre of the object.

Example forces on a car:

  • Weight (W, downward)
  • Normal reaction force from road (R, upward)
  • Driving force (F_drive, forward)
  • Air resistance / friction (F_drag, backward)

Resultant force = F_drive − F_drag (horizontal).

If F_drive > F_drag → net forward force → accelerates. If F_drive = F_drag → zero net force → constant velocity.

Terminal velocity

Objects falling through a fluid (air, water) eventually reach terminal velocity when the drag force equals the weight.

  1. Initially, weight > drag → net downward force → accelerates.
  2. As speed increases, drag increases.
  3. Eventually drag = weight → resultant force = 0 → constant velocity (terminal velocity).

Common mistakes

  1. F is resultant force, not individual force — if a 5 N force right and 3 N force left, F = 2 N right.
  2. Newton's 3rd law pairs act on DIFFERENT objects — they cannot cancel each other.
  3. Weight ≠ mass: weight W = mg (newtons); mass m (kg) is constant.
  4. Terminal velocity = constant velocity, not maximum speed that increases — it is a fixed value where drag balances weight.

AI-generated · claude-opus-4-7 · v3-edexcel-combined-science

Practice questions

Try each before peeking at the worked solution.

  1. Question 17 marks

    F = ma calculations

    (a) A 2500 kg lorry accelerates at 1.5 m/s². Calculate the resultant force acting on the lorry. [2 marks]

    (b) A resultant force of 800 N acts on a car, causing an acceleration of 2 m/s². Calculate the mass of the car. [2 marks]

    (c) A rocket of mass 50,000 kg has engines producing a thrust of 800,000 N. The weight of the rocket is 500,000 N. Calculate the acceleration of the rocket at launch. [3 marks]

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-edexcel-combined-science

  2. Question 25 marks

    Newton's Third Law pairs

    A horse pulls a cart with a force of 600 N. A student says: "By Newton's Third Law, the cart pulls the horse back with 600 N, so the forces cancel and nothing can move."

    (a) Identify the error in the student's reasoning. [2 marks]

    (b) The horse has mass 500 kg and the cart has mass 300 kg. There is a friction force of 100 N opposing the cart's motion. Calculate the acceleration of the system. [3 marks]

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    AI-generated · claude-opus-4-7 · v3-edexcel-combined-science

  3. Question 36 marks

    Terminal velocity — 6-mark extended response

    A skydiver jumps from a plane. Describe and explain the motion of the skydiver from the moment they jump until they reach terminal velocity, and then after they open their parachute.

    [6 marks]

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    AI-generated · claude-opus-4-7 · v3-edexcel-combined-science

Flashcards

CP2.2 — Newton's laws of motion and F = ma

8-card SR deck for Edexcel Combined Science topic CP2.2

8 cards · spaced repetition (SM-2)