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GCSE/Combined Science/OCR· Higher tier

C5.1Monitoring chemical reactions: concentration, moles and titrations (HT)

Notes

Monitoring reactions: moles, concentration and titrations (Higher)

The mole

One mole = 6.02 × 10²³ particles (Avogadro's constant). The mass of one mole of a substance, in grams, equals its relative formula mass (Mr). Example: 1 mol H₂O = 18 g; 1 mol NaCl = 58.5 g.

n = mass / Mr n = c × V (V in dm³, c in mol/dm³)

Concentration

Concentration is amount of solute per unit volume. Two units appear in OCR papers:

  • mass concentration: g/dm³
  • molar concentration: mol/dm³

To convert: c (mol/dm³) = c (g/dm³) ÷ Mr.

Remember: 1 dm³ = 1000 cm³ = 1 litre.

Titration (PAG C4)

Titration finds the exact volume of one solution that reacts with a known volume of another, used here for acid–alkali neutralisation.

  1. Pipette 25.0 cm³ of alkali into a conical flask, add 2–3 drops phenolphthalein (pink in alkali).
  2. Fill burette with acid, take initial reading to 0.05 cm³.
  3. Add acid, swirling, until the colour just disappears — this is the end-point.
  4. Repeat until at least two concordant titres (within 0.10–0.20 cm³).
  5. Use the mean concordant titre.

Worked example

25.0 cm³ of NaOH (0.100 mol/dm³) is exactly neutralised by 22.50 cm³ of HCl. Find c(HCl).

n(NaOH) = 0.100 × (25.0 / 1000) = 0.00250 mol 1:1 ratio in NaOH + HCl → NaCl + H₂O, so n(HCl) = 0.00250 mol c(HCl) = 0.00250 / (22.50 / 1000) = 0.111 mol/dm³ (3 s.f.)

OCR exam tip

Always state significant figures and units. Common loss-of-mark errors: forgetting to convert cm³ → dm³, using the unrounded value once and the rounded value later, or quoting an answer to 4 s.f. when only 3 are justified.

AI-generated · claude-opus-4-7 · v3-ocr-combined-science-leaves

Practice questions

Try each before peeking at the worked solution.

  1. Question 12 marks

    Convert g/dm³ to mol/dm³

    OCR Paper C2 (Higher)

    A solution of sodium hydroxide has a concentration of 8.0 g/dm³. (Mr of NaOH = 40)

    Calculate its concentration in mol/dm³. (2 marks)

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    AI-generated · claude-opus-4-7 · v3-ocr-combined-science-leaves

  2. Question 24 marks

    Titration calculation

    OCR Paper C2 (Higher) — PAG C4

    A student titrates 25.0 cm³ of 0.150 mol/dm³ NaOH against H₂SO₄. The mean concordant titre is 18.75 cm³.

    Calculate the concentration of the H₂SO₄, in mol/dm³, to 3 s.f. The equation is 2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O. (4 marks)

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    AI-generated · claude-opus-4-7 · v3-ocr-combined-science-leaves

  3. Question 33 marks

    Concordant titres

    OCR Paper C2 (Higher)

    A student records four titres: 24.10, 23.45, 23.50, 23.40 cm³.

    (a) State which titres are concordant. (1 mark)
    (b) Calculate the mean titre to use in the calculation. (2 marks)

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    AI-generated · claude-opus-4-7 · v3-ocr-combined-science-leaves

Flashcards

C5.1 — Monitoring chemical reactions: concentration, moles and titrations (HT)

7-card SR deck for OCR GCSE Combined Science — Leaves (batch 1) topic C5.1

7 cards · spaced repetition (SM-2)