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GCSE/Combined Science/OCR

P3.2Simple circuits: current, potential difference, resistance, Ohm’s law and IV characteristics

Notes

Simple circuits and Ohm's law

Key quantities

  • Current (I) — rate of flow of charge, measured in amperes A using an ammeter placed in series. Q = I × t (charge in coulombs).
  • Potential difference (V) — energy transferred per unit charge, measured in volts (V) using a voltmeter placed in parallel across the component.
  • Resistance (R) — opposition to current, measured in ohms (Ω).

Ohm's law

V = I × R

For an ohmic conductor at constant temperature, V is directly proportional to I — the resistance R is constant. A graph of V (y) vs I (x) is a straight line through the origin.

Series vs parallel circuits

SeriesParallel
CurrentSame everywhereSplits between branches
p.d.Shared between componentsSame across each branch
Total RR₁ + R₂ + ...Less than smallest R
If one breaksWhole circuit stopsOther branches keep working

Household lighting uses parallel so that switches work independently and one bulb failing doesn't break the rest.

IV characteristics

  • Fixed resistor at constant T → straight line through origin (ohmic).
  • Filament lamp → S-shaped (curved) — as current rises, lamp heats up, R increases, line bends away from straight.
  • Diode → current flows in one direction only (forward bias above ~0.7 V); zero current in reverse.

OCR PAG P5

Investigate the IV characteristic of a fixed resistor and a filament lamp. Use a low-voltage power supply, ammeter in series, voltmeter in parallel, vary V (or use a variable resistor), record I.

Worked example

A 12 V supply drives 3 A through a heater. R = V/I = 12/3 = 4 Ω.

OCR exam tip

When asked why the lamp's IV graph isn't straight, say "the filament heats up, atoms vibrate more, electrons collide more, resistance increases as current rises". Three steps, three marks.

AI-generated · claude-opus-4-7 · v3-ocr-combined-science-leaves

Practice questions

Try each before peeking at the worked solution.

  1. Question 13 marks

    Calculate resistance

    OCR Paper P1 (Foundation)

    A current of 0.50 A flows through a component when the potential difference across it is 6.0 V.

    Calculate the resistance of the component. State the unit. (3 marks)

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-ocr-combined-science-leaves

  2. Question 22 marks

    Series vs parallel

    OCR Paper P1 (Foundation)

    State two reasons why household lighting circuits are wired in parallel rather than in series. (2 marks)

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-ocr-combined-science-leaves

  3. Question 33 marks

    Filament lamp IV graph

    OCR Paper P1 (Higher) — PAG P5

    Explain why the IV characteristic graph of a filament lamp is curved rather than a straight line. (3 marks)

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-ocr-combined-science-leaves

Flashcards

P3.2 — Simple circuits: current, potential difference, resistance, Ohm's law and IV characteristics

7-card SR deck for OCR GCSE Combined Science — Leaves (batch 2) topic P3.2

7 cards · spaced repetition (SM-2)