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GCSE/Physics/CCEA

U1.2Forces — Newton's laws, momentum, terminal velocity, stopping distances

Notes

Forces

Newton's three laws of motion

First law: An object remains at rest or moves at constant velocity unless acted upon by a resultant force. (Inertia — objects resist changes to their motion.)

Second law: Resultant force = mass × acceleration. F = ma (SI units: N = kg × m/s²). A larger force produces a larger acceleration; a larger mass produces a smaller acceleration for the same force.

Third law: When object A exerts a force on object B, object B exerts an equal and opposite force on object A. These forces act on different objects and are of the same type. Example: a book rests on a table — the book's weight pushes down on the table (gravitational force); the table pushes up on the book with an equal normal contact force. CCEA questions often ask you to identify the Newton's 3rd law pair.

Weight and mass

Weight (W) is the gravitational force on a mass: W = mg where g = 9.8 N/kg (= 9.8 m/s² on Earth). Mass is constant; weight depends on the gravitational field strength.

Free body diagrams

A free body diagram shows all forces acting on a single object as arrows. Correctly label:

  • Weight (down, from centre of gravity)
  • Normal contact force / reaction (perpendicular to surface)
  • Friction (opposing motion)
  • Air resistance / drag (opposing motion)
  • Tension (along string/rope)
  • Applied force

Resultant force = vector sum of all forces. If resultant = 0, the object is in equilibrium.

Terminal velocity (extended)

As an object falls: weight acts down; drag acts up. Initially weight > drag → object accelerates. As speed increases, drag increases. Eventually drag = weight → resultant force = 0 → constant velocity (terminal velocity). A v-t graph shows a curve that levels off at terminal velocity.

Momentum

Momentum (p) = mass × velocity: p = mv (units: kg m/s). Momentum is a vector.

Conservation of momentum: In a closed system (no external forces), total momentum before = total momentum after. p_before = p_after → m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

Impulse: Force × time = change in momentum: F × t = Δ(mv) = mv − mu. Crash safety features (crumple zones, air bags) increase collision time → reduce force for same momentum change.

Stopping distances

Stopping distance = thinking distance + braking distance.

  • Thinking distance: distance covered during reaction time (typically 0.7 s). Increased by alcohol, drugs, tiredness, distraction, higher speed.
  • Braking distance: distance to stop after brakes applied. Depends on speed (quadratic — doubles speed → 4× braking distance), road conditions, tyre condition, brake condition, vehicle mass.

CCEA Higher questions sometimes ask you to calculate stopping distances using v² = u² + 2as.

Common mistakes

  1. Confusing mass and weight — mass in kg, weight in N. Never say "weight = 70 kg."
  2. Third law pairs acting on the same object — they always act on different objects.
  3. Forgetting units for momentum — must be kg m/s.
  4. Not conserving momentum with sign conventions — choose positive direction and be consistent.

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Practice questions

Try each before peeking at the worked solution.

  1. Question 17 marks

    Apply Newton's second law

    CCEA Unit 1 Paper

    A car of mass 1200 kg accelerates at 2.5 m/s².

    (a) Calculate the resultant force acting on the car. (2 marks)
    (b) The engine provides a driving force of 4200 N. Calculate the resistive forces acting on the car. (2 marks)
    (c) The driver releases the throttle; the driving force drops to zero. If resistive forces remain 1200 N, calculate the deceleration. (3 marks)

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  2. Question 26 marks

    Conservation of momentum

    CCEA Unit 1 Paper

    Two ice hockey pucks slide on a frictionless ice rink. Puck A (0.16 kg) moves at 3 m/s east and collides with stationary puck B (0.24 kg). After the collision puck A is stationary.

    (a) Calculate the momentum of puck A before the collision. (2 marks)
    (b) Calculate the velocity of puck B after the collision. (3 marks)
    (c) State the law you used in (b). (1 mark)

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  3. Question 36 marks

    Terminal velocity — describe using Newton's laws

    CCEA Unit 1 Paper — 6-mark extended answer

    A skydiver jumps from a plane. Describe how and why the skydiver's velocity changes from the moment of jumping until terminal velocity is reached. You should refer to Newton's laws in your answer. (6 marks)

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  4. Question 48 marks

    Stopping distances

    CCEA Unit 1 Paper

    A car travels at 20 m/s. The driver's reaction time is 0.6 s. The braking deceleration is 8 m/s².

    (a) Calculate the thinking distance. (2 marks)
    (b) Calculate the braking distance using v² = u² + 2as. (3 marks)
    (c) Calculate the total stopping distance. (1 mark)
    (d) Explain why the braking distance increases if the road is wet. (2 marks)

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  5. Question 57 marks

    Newton's third law — identify action-reaction pairs

    CCEA Unit 1 Paper

    (a) State Newton's third law of motion. (1 mark)
    (b) A person stands on a floor. Identify a Newton's third law pair of forces, stating the force, the object it acts on, and the direction of each force. (3 marks)
    (c) A rocket expels gas downward at high speed. Explain, using Newton's third law, why the rocket accelerates upward. (3 marks)

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Flashcards

U1.2 — Forces — Newton's laws, momentum, terminal velocity, stopping distances

10-card SR deck for CCEA Physics topic U1.2

10 cards · spaced repetition (SM-2)