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GCSE/Physics/Edexcel

CP2Forces and motion — Newton's laws, mass vs weight, momentum, terminal velocity, stopping distances

Notes

Forces and Motion

Newton's Three Laws of Motion

First Law: An object remains at rest or moves at constant velocity unless acted upon by a resultant force.

Implication: if an object is stationary or moving at constant speed, all forces are balanced (resultant = 0).

Second Law: The resultant force on an object is directly proportional to the acceleration it produces and inversely proportional to the object's mass.

F = ma (resultant force in N, mass in kg, acceleration in m/s²)

Third Law: When object A exerts a force on object B, object B exerts an equal and opposite force on object A.

These forces act on different objects — they are NOT balanced forces. Example: Earth pulls you down (gravity), you pull Earth up (equal magnitude, opposite direction).

Mass and Weight

  • Mass (kg): the amount of matter in an object. It does not change with location.
  • Weight (N): the gravitational force on an object. W = mg.
  • On Earth: g ≈ 9.8 N/kg (use 10 N/kg unless told otherwise in Edexcel).
  • On the Moon (g ≈ 1.6 N/kg): a 70 kg person weighs 70 × 1.6 = 112 N.

Resultant Forces and Free Body Diagrams

When multiple forces act on an object, find the resultant (net) force:

  • Collinear forces (same line): add/subtract.
  • Perpendicular forces: use Pythagoras.

Free body diagrams show all forces acting on a single object as arrows from a centre dot, labelled with size and direction.

Terminal Velocity

A falling object experiences:

  1. Weight (downward) — constant.
  2. Air resistance / drag (upward) — increases with speed.

Initially weight > drag → accelerates. As speed increases, drag increases → resultant force decreases → acceleration decreases. When drag = weight → terminal velocity (constant speed, zero acceleration).

Parachutist example: opens parachute → drag suddenly increases greatly → resultant force upward → decelerates → new (lower) terminal velocity reached.

Momentum

Momentum (p) = mass × velocity (unit: kg m/s).

Conservation of momentum: in a closed system (no external forces), total momentum before = total momentum after.

For a collision: m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

Impulse = force × time = change in momentum (Ft = mv − mu)

Airbags and crumple zones increase collision time → reduce force for same momentum change → safer.

Core Practical 2 — Investigating Force, Mass and Acceleration

Equipment: dynamics trolley, ramp (compensated for friction), hanging masses on string over pulley, light gates + data logger (or ticker tape).

Method:

  1. Keep total system mass constant. Vary the hanging mass (force) and measure acceleration.
  2. Then keep force constant; add masses to the trolley and measure acceleration.

Results:

  • a ∝ F (at constant mass): graph of a vs F is a straight line through origin.
  • a ∝ 1/m (at constant force): graph of a vs 1/m is a straight line through origin.

Key detail: the mass of the hanging mass string must be small compared to total system mass, otherwise you can't treat the hanging mass as a force alone.

AI-generated · claude-opus-4-7 · v3-edexcel-physics

Practice questions

Try each before peeking at the worked solution.

  1. Question 18 marks

    Newton's Second Law — F = ma calculation

    Edexcel 1PH0 Paper 1

    A resultant force of 360 N acts on a car of mass 1200 kg.

    (a) Calculate the acceleration of the car. (2 marks)
    (b) The car reaches 24 m/s from rest under this acceleration. Calculate the distance travelled. (3 marks)
    (c) State Newton's First Law and explain what happens when the engine force equals the drag force on the car. (3 marks)

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    AI-generated · claude-opus-4-7 · v3-edexcel-physics

  2. Question 26 marks

    Terminal velocity explanation (6-mark QWC)

    Edexcel 1PH0 Paper 1 — Quality of Written Communication

    Describe and explain the motion of a skydiver from the moment they jump from a plane until they reach terminal velocity before opening their parachute. (6 marks)

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    AI-generated · claude-opus-4-7 · v3-edexcel-physics

  3. Question 38 marks

    Momentum and conservation

    Edexcel 1PH0 Paper 1

    A 0.4 kg ball moving at 6 m/s to the right collides with a stationary 0.6 kg ball. After the collision the 0.4 kg ball continues at 1 m/s to the right.

    (a) Calculate the momentum of the system before the collision. (2 marks)
    (b) Calculate the velocity of the 0.6 kg ball after the collision. (3 marks)
    (c) Is kinetic energy conserved in this collision? Show your working. (3 marks)

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    AI-generated · claude-opus-4-7 · v3-edexcel-physics

  4. Question 45 marks

    Weight and gravitational field strength

    Edexcel 1PH0 Paper 1

    An astronaut has a mass of 80 kg. The gravitational field strength on Mars is 3.7 N/kg.

    (a) Calculate the astronaut's weight on Mars. (2 marks)
    (b) Calculate the astronaut's weight on Earth (g = 9.8 N/kg). (1 mark)
    (c) Explain why the astronaut's mass is the same on both planets but their weight is different. (2 marks)

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    AI-generated · claude-opus-4-7 · v3-edexcel-physics

Flashcards

CP2 — Forces and motion — Newton's laws, mass vs weight, momentum, terminal velocity, stopping distances

8-card SR deck for Edexcel Physics topic CP2

8 cards · spaced repetition (SM-2)