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GCSE/Physics/WJEC

U1.1Electric circuits — current, p.d., resistance, series and parallel, IV characteristics

Notes

Electric Circuits

Current, Charge and Potential Difference

Electric current (I) is the rate of flow of charge: I = Q/t, where Q is charge in coulombs C and t is time in seconds. Current is measured in amperes A using an ammeter connected in series.

Potential difference (p.d. or voltage, V) is the energy transferred per unit charge: V = W/Q (energy in joules, charge in coulombs). P.d. is measured in volts (V) using a voltmeter connected in parallel.

Resistance (R) opposes the flow of current. From Ohm's law: V = IR (volts = amps × ohms). Rearranging: I = V/R and R = V/I.

Series and Parallel Circuits

Series circuits

  • Same current flows through every component: I_total = I₁ = I₂ = I₃
  • Total p.d. is shared: V_total = V₁ + V₂ + V₃
  • Total resistance adds: R_total = R₁ + R₂ + R₃
  • If one component breaks, the circuit is broken — all components stop working.

Parallel circuits

  • Total current splits: I_total = I₁ + I₂ + I₃
  • Same p.d. across each branch: V_total = V₁ = V₂ = V₃
  • Total resistance is less than the smallest branch resistance: 1/R_total = 1/R₁ + 1/R₂ + 1/R₃
  • If one branch breaks, the rest continue working.

IV Characteristics (Required Practical)

The IV characteristic of a component is a graph of current (y-axis) against voltage (x-axis). WJEC requires you to investigate the IV characteristics of three components:

Resistor (ohmic conductor)

A straight line through the origin — current is directly proportional to voltage. Slope = 1/R. The resistance is constant regardless of voltage.

Lamp (filament bulb)

S-shaped curve — as voltage increases, current increases but the slope decreases. The filament heats up, increasing resistance. At higher voltages, the graph curves away from the straight line (resistance is not constant).

Diode

Near-zero current for negative voltages (reverse bias). A sharp turn-on at about +0.6V (forward threshold), then current rises steeply. Diodes only let current flow in one direction.

Practical Tip (WJEC Required Practical)

To obtain IV characteristics: connect the component to a variable power supply with an ammeter in series and voltmeter in parallel. Vary the voltage, reading both meters at each setting. Plot I (y-axis) against V (x-axis). Repeat with reverse connections for the diode.

Common mistakes

  1. Ammeter and voltmeter positions swapped: ammeter goes in series (same current flows through it), voltmeter in parallel (same p.d. across it). Swapping them gives wrong readings and can blow fuses.
  2. Ohm's law rearrangement errors: if you double the voltage and keep R constant, current doubles (not halves). Write the formula triangle V / I R if it helps.
  3. Series resistance addition applied to parallel: in parallel, total R is always less than the smallest individual R.
  4. Confusing current and charge: current is charge per second (I = Q/t); charge is not the same as current.
  5. Diode IV curve drawn symmetrically: the forward and reverse branches look very different — don't draw a symmetric S-curve.

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Practice questions

Try each before peeking at the worked solution.

  1. Question 16 marks

    Ohm's law calculation

    WJEC Unit 1 — Foundation/Higher

    A resistor has a resistance of 15 Ω. A potential difference of 6 V is applied across it.

    (a) Calculate the current through the resistor. State the equation used. (3 marks)
    (b) A second resistor of 25 Ω is connected in series with the first. Calculate the total resistance. (1 mark)
    (c) Calculate the new current from the same 6 V supply. (2 marks)

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  2. Question 29 marks

    Series vs parallel comparison

    WJEC Unit 1 — Foundation

    Two identical lamps, each with resistance 10 Ω, are connected to a 12 V battery.

    (a) The lamps are connected in series. Calculate: (i) the total resistance; (ii) the current; (iii) the p.d. across each lamp. (4 marks)
    (b) The lamps are connected in parallel. Calculate: (i) the total resistance; (ii) the total current from the battery. (3 marks)
    (c) Which arrangement gives brighter lamps? Explain your answer. (2 marks)

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  3. Question 38 marks

    IV characteristics — describe and explain

    WJEC Unit 1 — Higher

    The diagram below shows IV characteristics for three components: a resistor, a filament lamp and a diode. [Imagine three curves labelled A, B, C.]

    (a) Identify which curve (A, B or C) represents each component. Justify your answer. (3 marks)
    (b) Explain, in terms of resistance, why the filament lamp's IV graph is curved rather than straight. (3 marks)
    (c) Use the graph for the resistor to determine its resistance at a particular point (e.g. I = 0.4 A, V = 2 V). Show your working. (2 marks)

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  4. Question 46 marks

    Charge and current calculation

    WJEC Unit 1 — Foundation/Higher

    A current of 2.5 A flows through a wire for 4 minutes.

    (a) State the equation linking charge, current and time. (1 mark)
    (b) Calculate the total charge that flows. Give the unit. (3 marks)
    (c) How many electrons pass a point if each electron carries a charge of 1.6 × 10⁻¹⁹ C? (2 marks)

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  5. Question 59 marks

    Required practical — designing an IV investigation

    WJEC Unit 1 Required Practical — Higher

    A student wants to obtain the IV characteristic of a filament lamp.

    (a) Draw a circuit diagram for this investigation, including all necessary meters. Label each component. (3 marks)
    (b) Describe how the student would vary the voltage across the lamp and what measurements they would take. (3 marks)
    (c) Sketch the expected IV characteristic of the filament lamp, labelling the axes. (2 marks)
    (d) Explain one precaution the student should take to improve the quality of results. (1 mark)

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Flashcards

U1.1 — Electric circuits — current, p.d., resistance, series and parallel, IV characteristics

10-card SR deck for WJEC Physics topic U1.1

10 cards · spaced repetition (SM-2)