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GCSE/Physics/WJEC

U1.5Distance, speed, acceleration — equations of motion, distance-time and velocity-time graphs

Notes

Distance, Speed and Acceleration

Key Quantities

  • Distance (s): how far an object travels, regardless of direction. Scalar. Unit: m.
  • Displacement: distance in a specified direction. Vector.
  • Speed (v): rate of change of distance. Scalar. v = d/t.
  • Velocity: speed in a specified direction. Vector.
  • Acceleration (a): rate of change of velocity. a = Δv/t = (v−u)/t. Unit: m/s².

Equations of Motion (WJEC Unit 1)

For uniform (constant) acceleration:

  1. v = u + at (final velocity = initial + acceleration × time)
  2. s = ut + ½at² (displacement = initial velocity × time + ½ × acceleration × time²)
  3. v² = u² + 2as (relates velocities and displacement without time)
  4. s = ½(u + v)t (displacement = average velocity × time)

Where: u = initial velocity (m/s), v = final velocity (m/s), a = acceleration (m/s²), t = time (s), s = displacement (m).

Distance-Time Graphs

  • Horizontal line: object is stationary (distance not changing).
  • Straight line with positive slope: constant speed. Gradient = speed.
  • Curve (steepening): accelerating.
  • Curve (flattening): decelerating.

Speed from d-t graph = gradient = Δdistance/Δtime.

Velocity-Time Graphs

  • Horizontal line: constant velocity (zero acceleration).
  • Straight line with positive slope: uniform acceleration. Gradient = acceleration.
  • Straight line with negative slope: uniform deceleration. Gradient = acceleration (negative).
  • Area under graph = displacement (distance if always positive velocity).

Acceleration from v-t graph = gradient = Δvelocity/Δtime.

Acceleration Due to Gravity

On Earth, g ≈ 10 m/s² (or 9.8 m/s²). A falling object (ignoring air resistance) accelerates at 10 m/s²; it gains 10 m/s of speed every second.

Terminal velocity: when drag force = weight, acceleration = 0 and the object falls at constant velocity. Skydivers reach terminal velocity at ~55 m/s (with arms/legs out) or ~80 m/s (diving).

WJEC Required Practical: Investigating Motion

Students use a light gate + data logger (or ticker tape + ticker timer) to measure velocity at different points to calculate acceleration. Plotting v-t gives a straight line whose gradient is a.

Common mistakes

  1. Gradient on a d-t graph = speed, not acceleration: acceleration is the gradient of a v-t graph.
  2. Area on a v-t graph = displacement: students sometimes think area = acceleration.
  3. Forgetting to square in v² = u² + 2as: double-check the algebra.
  4. Speed vs velocity: speed is a scalar (magnitude only); velocity is a vector (has direction). An object can travel at constant speed but changing velocity (circular motion).

AI-generated · claude-opus-4-7 · v3-wjec-physics

Practice questions

Try each before peeking at the worked solution.

  1. Question 18 marks

    Equations of motion — car braking

    WJEC Unit 1 — Foundation/Higher

    A car travelling at 20 m/s brakes and comes to rest. The braking distance is 40 m.

    (a) Calculate the deceleration of the car during braking. (3 marks)
    (b) Calculate the time taken to stop. (3 marks)
    (c) Sketch a velocity-time graph for the car's braking. Label both axes. (2 marks)

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    AI-generated · claude-opus-4-7 · v3-wjec-physics

  2. Question 27 marks

    Interpret a distance-time graph

    WJEC Unit 1 — Foundation

    A distance-time graph shows three sections: Section A (0–10 s, 0–50 m), Section B (10–20 s, 50 m constant), Section C (20–30 s, 50–20 m).

    (a) Calculate the speed during Section A. (2 marks)
    (b) Describe the motion during Section B. (1 mark)
    (c) Calculate the speed during Section C. (2 marks)
    (d) Describe the motion during Section C and state the direction of travel. (2 marks)

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    AI-generated · claude-opus-4-7 · v3-wjec-physics

  3. Question 37 marks

    Velocity-time graph — area and acceleration

    WJEC Unit 1 — Higher

    A velocity-time graph shows a car accelerating uniformly from 0 m/s to 30 m/s in 12 s, then travelling at constant velocity for 8 s, then decelerating to rest in 6 s.

    (a) Calculate the acceleration in the first phase. (2 marks)
    (b) Calculate the distance travelled in each of the three phases (area under graph). (4 marks)
    (c) Calculate the total distance. (1 mark)

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    AI-generated · claude-opus-4-7 · v3-wjec-physics

  4. Question 47 marks

    Free fall and terminal velocity

    WJEC Unit 1 — Higher

    A skydiver jumps from a plane. Initially she falls with acceleration close to 10 m/s². Over time, her acceleration decreases until she reaches terminal velocity.

    (a) Using the equation v = u + at, calculate her velocity after 3 s of free fall from rest, assuming constant acceleration of 10 m/s². (2 marks)
    (b) Explain, in terms of forces, why her acceleration decreases as she falls faster. (3 marks)
    (c) Explain what is meant by terminal velocity and the condition for reaching it. (2 marks)

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    AI-generated · claude-opus-4-7 · v3-wjec-physics

Flashcards

U1.5 — Distance, speed, acceleration — equations of motion, distance-time and velocity-time graphs

10-card SR deck for WJEC Physics topic U1.5

10 cards · spaced repetition (SM-2)