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GCSE/Chemistry/AQA· Higher tier

C5.3Bond energy calculations (HT): using bond energies to calculate overall energy change of a reaction

Notes

Calculating energy change from bond energies (HT)

The total energy change of a reaction is the difference between the energy needed to break bonds (in reactants) and the energy released when new bonds form (in products).

The key formula

ΔE = (energy in to break bonds) − (energy out forming bonds)

Or equivalently:

ΔE = sum of bond energies (reactants) − sum of bond energies (products)

Note: bond energies are positive numbers (energy required to break a bond).

Sign convention

  • Negative ΔE → exothermic (more energy released than absorbed).
  • Positive ΔE → endothermic (more energy absorbed than released).

Method (step-by-step)

  1. Write the balanced equation.
  2. Draw the displayed (full structural) formulae to count bonds.
  3. List bonds in reactants × number of each.
  4. List bonds in products × number of each.
  5. ΔE = sum(reactant bonds) − sum(product bonds).

Worked exampleWorked example: H₂ + Cl₂ → 2HCl

Bonds in reactants:

  • 1 × H–H = 436 kJ/mol
  • 1 × Cl–Cl = 243 kJ/mol
  • Total = 679 kJ/mol

Bonds in products:

  • 2 × H–Cl = 2 × 432 = 864 kJ/mol

ΔE = 679 − 864 = −185 kJ/mol → exothermic.

Worked exampleWorked example: combustion of methane

CH₄ + 2O₂ → CO₂ + 2H₂O

Bond energies (kJ/mol): C–H 413, O=O 498, C=O 805, O–H 463.

Reactants:

  • 4 × C–H = 1652
  • 2 × O=O = 996
  • Total = 2648

Products:

  • 2 × C=O = 1610
  • 4 × O–H = 1852
  • Total = 3462

ΔE = 2648 − 3462 = −814 kJ/mol → exothermic.

Why the formula works

Breaking bonds costs energy; making bonds gives energy back. If more is given back (products) than was paid (reactants), the reaction is exothermic and energy is released to the surroundings.

Common mistakes

  • Forgetting to multiply by the number of bonds. CH₄ has FOUR C–H bonds, not one.
  • Wrong sign. ΔE = reactants − products (not products − reactants).
  • Using bond ENTHALPY values from a different table — answers will differ from mark scheme.
  • Counting bonds in molecules incorrectly — draw out the displayed formulae.

Links

Extends C5.1, C5.2. Used in C7.3 (combustion energy of fuels) and links to A-level enthalpy.

AI-generated · claude-opus-4-7 · v3-deep-chemistry

Practice questions

Try each before peeking at the worked solution.

  1. Question 11 mark

    Method (H)

    (H1) State the formula for calculating overall energy change from bond energies.

    [Higher — 1 mark]

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  2. Question 23 marks

    H₂ + Cl₂ (H)

    (H2) Calculate ΔE for H₂ + Cl₂ → 2HCl using H–H 436, Cl–Cl 243, H–Cl 432.

    [Higher — 3 marks]

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  3. Question 34 marks

    CH₄ combustion (H)

    (H3) Calculate ΔE for CH₄ + 2O₂ → CO₂ + 2H₂O using C–H 413, O=O 498, C=O 805, O–H 463.

    [Higher — 4 marks]

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  4. Question 42 marks

    Identify exo/endo (H)

    (H4) A reaction has reactant bond energies totalling 1500 kJ and product bond energies totalling 1700 kJ. State and justify whether it is exothermic or endothermic.

    [Higher — 2 marks]

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  5. Question 53 marks

    H₂ + Br₂ (H)

    (H5) Calculate ΔE for H₂ + Br₂ → 2HBr using H–H 436, Br–Br 193, H–Br 366.

    [Higher — 3 marks]

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  6. Question 62 marks

    Significance (H)

    (H6) Explain in words why combustion of methane is exothermic, in terms of bond energies.

    [Higher — 2 marks]

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  7. Question 74 marks

    Hydrogenation (H)

    (H7) Calculate ΔE for ethene + H₂ → ethane: C=C 614, C–H 413, H–H 436, C–C 347.

    [Higher — 4 marks]

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Flashcards

C5.3 — Bond energies (HT)

10-card HT deck on bond-energy calculations and worked examples.

10 cards · spaced repetition (SM-2)