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GCSE/Combined Science/WJEC· Higher tier

P5.2Motion: distance, displacement, speed, velocity, acceleration; SUVAT for uniform acceleration (HT)

Notes

Motion: speed, velocity and acceleration

Scalars vs vectors

  • Scalar quantities have size only: distance, speed, mass.
  • Vector quantities have size AND direction: displacement, velocity, acceleration, force.

Distance is the total path length travelled. Displacement is the straight-line distance from start to finish in a stated direction.

Speed and velocity

speed = distance / time. Units: m/s.

velocity = displacement / time. Same units, but with a direction (e.g. 20 m/s east).

Acceleration

acceleration = change in velocity / time taken.

a = (v - u) / t

Units: m/s^2. Negative acceleration is deceleration.

SUVAT for uniform acceleration (Higher tier)

For motion with constant acceleration, WJEC uses:

v^2 = u^2 + 2 a s

Where:

  • u = initial velocity (m/s)
  • v = final velocity (m/s)
  • a = acceleration (m/s^2)
  • s = displacement (m)

Worked example: a car accelerates from rest at 2 m/s^2 over 50 m. Find v.

  • u = 0, a = 2, s = 50.
  • v^2 = 0 + 2 x 2 x 50 = 200.
  • v = sqrt(200) = 14.1 m/s.

Distance-time and velocity-time graphs

  • Distance-time: gradient = speed. Horizontal line = stationary.
  • Velocity-time: gradient = acceleration. Area under the line = distance travelled.

WJEC exam tip

Watch for trick questions that ask for displacement when an object returns to start. The distance can be 100 m but the displacement zero. Read every motion question for the precise quantity asked.

AI-generated · claude-opus-4-7 · v3-wjec-combined-science-leaves

Practice questions

Try each before peeking at the worked solution.

  1. Question 14 marks

    Acceleration calculation

    WJEC Unit 2 Physics — Foundation tier

    A cyclist accelerates from 4 m/s to 12 m/s in 4 s.

    (a) Calculate the acceleration. (2 marks)
    (b) State whether this is a vector or a scalar quantity, with a reason. (2 marks)

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-wjec-combined-science-leaves

  2. Question 23 marks

    SUVAT — final velocity

    WJEC Unit 2 Physics — Higher tier

    A car starts from rest and accelerates uniformly at 3.0 m/s^2 over a distance of 24 m.

    Use v^2 = u^2 + 2 a s to calculate the final velocity. (3 marks)

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-wjec-combined-science-leaves

  3. Question 34 marks

    Distance vs displacement

    WJEC Unit 2 Physics — Higher tier

    A runner completes one lap of a 400 m circular track in 80 s, returning to the start.

    (a) State the total distance and the total displacement of the runner. (2 marks)
    (b) Calculate the average speed and the average velocity. (2 marks)

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-wjec-combined-science-leaves

Flashcards

P5.2 — Motion: distance, displacement, speed, velocity, acceleration; SUVAT for uniform acceleration (HT)

7-card SR deck for WJEC GCSE Combined Science (Double Award) — Leaves Batch 2 topic P5.2

7 cards · spaced repetition (SM-2)