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GCSE/Mathematics/AQA

G6Apply angle facts, congruence, similarity and quadrilateral properties

Notes

Applying angle facts, congruence, similarity and quadrilateral properties

This topic ties together G1-G5 — combining facts about angles, congruence and quadrilaterals into multi-step deductive problems.

Toolkit summary

You should be confident with:

  • Angles at a point = 360°.
  • Angles on a straight line = 180°.
  • Angles in a triangle = 180°.
  • Vertically opposite angles equal.
  • Parallel lines — corresponding/alternate equal; co-interior sum to 180°.
  • Quadrilateral angles sum to 360°.
  • Special quadrilaterals — properties (G4).
  • Congruence rules — SSS, SAS, ASA, RHS (G5).
  • Similar triangles — equal angles → corresponding sides in fixed ratio.
  • Isosceles triangles — base angles equal.

Multi-step problems

GCSE Higher questions typically combine 2-3 facts. Strategy:

  1. Identify what you're asked to find.
  2. Write down everything you know from the diagram (mark angle equalities).
  3. Look for triangles inside quadrilaterals or parallel lines.
  4. Apply ONE fact at a time, recording the reason.

Worked example

ABCD is a parallelogram. AC is a diagonal. ∠BAC = 32° and ∠ACD = 70°. Find ∠ABC.

Steps:

  1. ∠BAC = 32°. AB ∥ CD, so ∠ACD and ∠CAB are alternate angles (Z-shape) → ∠CAB = ∠ACD = 70°? Wait — re-read.
  2. Actually given ∠BAC = 32° and ∠ACD = 70°. Since AB ∥ CD, ∠BAC = ∠ACD if alternate; but they aren't equal here. Let me re-set: ∠BAD = ∠BAC + ∠CAD where ∠CAD is alternate to ∠ACB...
  3. Use triangle ACD: ∠ACD + ∠CAD + ∠ADC = 180°. ∠CAD is alternate to ∠ACB so equals (need that).
  4. In a typical setup: ∠ABC = 180° − ∠BAD = 180° − (32° + ∠CAD).

The point: write down each fact, justify it, build to the answer.

Similar triangles

If △ABC ~ △PQR (similar):

  • ∠A = ∠P, ∠B = ∠Q, ∠C = ∠R.
  • AB/PQ = BC/QR = CA/RP = scale factor.

Common mistakes

  1. Skipping reasons — Higher tier proofs need the reason for every step.
  2. Confusing congruent with similar — congruence requires equal sizes; similarity allows scaling.
  3. Wrongly identifying corresponding sides in similar triangles — the order matters: △ABC ~ △PQR means A↔P, B↔Q, C↔R.
  4. Mixing parallel-line rules with non-parallel-line situations — corresponding/alternate apply ONLY when lines are parallel.
  5. Not marking equal lengths/angles in the diagram — adds clarity for proofs.

Try thisQuick check

If △ABC ~ △DEF with AB = 6, DE = 9, and BC = 8, find EF.

  • Scale factor 9/6 = 1.5.
  • EF = 8 × 1.5 = 12.

AI-generated · claude-opus-4-7 · v3-deep-geometry

Practice questions

Try each before peeking at the worked solution.

  1. Question 12 marks

    Find angle in parallelogram

    (F1) In parallelogram ABCD, ∠ABC = 110°. Find ∠ADC.

    [Foundation tier]

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-deep-geometry

  2. Question 22 marks

    Triangle within parallelogram

    (F2) In parallelogram ABCD, diagonal AC is drawn. ∠CAB = 35° and ∠BCA = 50°. Find ∠ABC.

    [Foundation tier]

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-deep-geometry

  3. Question 33 marks

    Use parallel lines and triangle

    (F/H3) Lines AB and CD are parallel. A transversal meets them creating triangle ABE. Angle at A = 70°, angle at B = 60°. Find the third angle E and explain why ∠CDE could be calculated using parallel-line rules.

    [Crossover tier]

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    AI-generated · claude-opus-4-7 · v3-deep-geometry

  4. Question 43 marks

    Similar triangles

    (F/H4) △ABC ~ △PQR. AB = 4, BC = 5, AC = 6 cm. PQ = 6 cm. Find QR and PR.

    [Crossover tier]

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-deep-geometry

  5. Question 53 marks

    Isosceles within parallel lines

    (H5) In an isosceles triangle ABC, AB = AC. The base BC is parallel to a line ℓ. Show that any angle made by ℓ and AC equals the base angle of the triangle.

    [Higher tier]

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    AI-generated · claude-opus-4-7 · v3-deep-geometry

  6. Question 63 marks

    Multi-step angle chase

    (H6) ABCD is a kite with AB = AD and CB = CD. Diagonal AC is drawn. ∠BAC = 35° and ∠BCA = 50°. (a) Find ∠ABC. (b) Find ∠ADC.

    [Higher tier]

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    AI-generated · claude-opus-4-7 · v3-deep-geometry

  7. Question 74 marks

    Prove congruence + use it

    (H7) In parallelogram ABCD, M is the midpoint of AB. (a) Prove triangles AMD and BMC are congruent. (b) Hence state the length AD if BC = 8 cm.

    [Higher tier]

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    AI-generated · claude-opus-4-7 · v3-deep-geometry

Flashcards

G6 — Apply angle facts, congruence, similarity and quadrilateral properties

12-card SR deck for AQA GCSE Maths topic G6

12 cards · spaced repetition (SM-2)