Vectors and geometric proof
Vectors describe both magnitude (size) and direction. They appear in CCEA Higher tier and are often combined with geometric reasoning.
Vector notation
A vector can be written as:
- Bold letter: a or b.
- Column vector: $\begin{pmatrix} 3 \ -2 \end{pmatrix}$ (3 units right, 2 units down).
- Arrow notation: $\overrightarrow{AB}$ (from point A to point B).
Adding and subtracting vectors
Addition: place the second vector where the first ends (head-to-tail rule). a + b = travel along a then along b.
Subtraction: $\overrightarrow{AB} = \overrightarrow{OB} - \overrightarrow{OA}$ = b − a (where O is the origin).
Negative vector: −a has the same magnitude as a but opposite direction.
Scalar multiplication
ka is a vector in the same direction as a with magnitude scaled by k. If k is negative, the direction reverses.
Magnitude of a vector
For $\begin{pmatrix} x \ y \end{pmatrix}$: magnitude = $\sqrt{x^2 + y^2}$ (Pythagoras).
Position vectors
If O is the origin, the position vector of point A is $\overrightarrow{OA}$ = a. $\overrightarrow{AB} = \overrightarrow{OB} - \overrightarrow{OA}$ = b − a.
Vector paths and geometric proof
To find a vector path between two points, use the triangle law: $\overrightarrow{AC} = \overrightarrow{AB} + \overrightarrow{BC}$
Express everything in terms of the given vectors a and b (or p and q).
Proving collinearity: if $\overrightarrow{PQ} = k \overrightarrow{PR}$ (one is a scalar multiple of the other), and they share point P, then P, Q, R are collinear (on the same straight line).
Proving lines bisect: show that the midpoint vector of one line segment equals the midpoint vector of another.
CCEA examiner style
CCEA Higher vector questions typically:
- Give position vectors or set up a diagram with vector labels.
- Ask you to express $\overrightarrow{AB}$ in terms of given vectors.
- Ask you to prove a geometric result (midpoint, collinearity, parallelism).
Always show all steps in the vector path — do not skip from given to answer.
⚠Common mistakes
- Direction errors: $\overrightarrow{AB} = $ b − a, not a − b.
- Scalar multiplication: forgetting to multiply ALL components by the scalar.
- Collinearity: must show the vectors are parallel AND share a common point.
- Not simplifying fully: leaving ½(2a + 4b) instead of a + 2b.
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