TopMyGrade

GCSE/Mathematics/Edexcel

A15Calculate or estimate gradients and areas under graphs; interpret in context

Notes

Gradients and areas under graphs

This is a Higher topic on Edexcel 1MA1, examined regularly on Papers 2H and 3H. The skill: read or estimate a gradient or area from a graph and interpret the result.

Gradient under a curve

The gradient at a point on a curve = slope of the tangent at that point. See R15 for the tangent technique.

Area under a graph

For straight-line segments, decompose the region into rectangles, triangles, and trapezia.

  • Rectangle: A = base × height.
  • Triangle: A = (1/2) × base × height.
  • Trapezium: A = (1/2) × (a + b) × h, where a and b are the parallel sides and h is the perpendicular distance.

Estimating area under a curve — trapezium rule (informal)

Divide the area into vertical strips of equal width h. For each strip, draw a trapezium connecting the curve at the left and right ends. Sum the trapezia:

A ≈ (h/2) × [y₀ + 2(y₁ + y₂ + ... + yₙ₋₁) + yₙ]

This is an estimate — narrower strips give a closer approximation.

Contextual interpretations

  • Velocity-time graph area = distance travelled.
  • Force-distance graph area = work done (in mechanics, IGCSE/A-Level only).
  • Rate-of-flow vs time area = total volume flowed.
  • Power-time area = energy.

Common Edexcel mark-scheme phrasing

  • M1 for valid decomposition into known shapes.
  • M1 for each shape's area calculation.
  • A1 for the total.
  • B1 for contextual interpretation with units.

Common mistakesCommon errors

  • Counting squares without using the axis scales.
  • Forgetting to multiply by (1/2) for a triangle.
  • Including only one strip in the trapezium rule (need at least 3–5 for a usable estimate).
  • Stating "distance travelled = 80" instead of "80 m" — units matter.

AI-generated · claude-opus-4-7 · v3-edexcel-maths-leaves

Practice questions

Try each before peeking at the worked solution.

  1. Question 15 marks

    Area under a velocity-time graph — Higher

    Edexcel Paper 2H — Higher

    A cyclist's velocity-time graph has three segments: a triangular acceleration from 0 to 8 m/s in 4 seconds, then a horizontal at 8 m/s for 6 seconds, then a triangular deceleration from 8 m/s to 0 in 2 seconds.

    (a) Find the total distance travelled. (4 marks)
    (b) Interpret the meaning of the area in context. (1 mark)

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-edexcel-maths-leaves

  2. Question 25 marks

    Estimate area under a curve — trapezium rule

    Edexcel Paper 3H — Higher

    The graph shows the speed v (m/s) of a runner over time t (s). Values from the graph at 2-second intervals are:

    t (s)02468
    v (m/s)04788

    (a) Use the trapezium rule with strips of width 2 to estimate the area under the curve from t = 0 to t = 8. (4 marks)
    (b) Interpret your answer in context, with units. (1 mark)

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-edexcel-maths-leaves

  3. Question 37 marks

    Gradient and area together — Higher

    Edexcel Paper 2H — Higher (QWC)

    A car's velocity-time graph is a straight line rising from 0 m/s at t = 0 to 30 m/s at t = 10 s, then horizontal at 30 m/s until t = 20 s.

    (a) Find the acceleration during the first 10 seconds. State units. (2 marks)
    (b) Find the total distance travelled in the 20 seconds. (3 marks)
    (c) State which feature of the graph (gradient or area) gave each answer, and why. (2 marks, QWC)

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-edexcel-maths-leaves

Flashcards

A15 — Calculate or estimate gradients and areas under graphs; interpret in context

7-card SR deck for Edexcel GCSE Mathematics (1MA1) — Leaves Batch 5 topic A15

7 cards · spaced repetition (SM-2)