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GCSE/Mathematics/Edexcel

A9Plot linear graphs; y = mx + c; parallel and perpendicular lines

Notes

Linear graphs

The equation y = mx + c

Every straight line can be written as y = mx + c where:

  • m = gradient (slope) — the change in y for every 1 unit increase in x.
  • c = y-intercept — the value of y when x = 0 (where the line crosses the y-axis).

Finding the gradient from a graph: gradient = rise ÷ run = (change in y) ÷ (change in x). Pick two points on the line and calculate.

Finding the equation from two points: calculate the gradient, then substitute one point into y = mx + c to find c.

Example: Points (2, 5) and (6, 13). m = (13 − 5)/(6 − 2) = 8/4 = 2. 5 = 2(2) + c → c = 1. Equation: y = 2x + 1.

Parallel lines

Parallel lines have the same gradient. If a line has gradient m, any parallel line is y = mx + k for a different constant k.

Perpendicular lines

If a line has gradient m, a perpendicular line has gradient −1/m (the negative reciprocal).

Example: a line with gradient 3 is perpendicular to a line with gradient −1/3. Example: gradient 2/3 → perpendicular gradient = −3/2.

Check: m₁ × m₂ = −1 for perpendicular lines.

Finding the equation of a line through a given point

Use y − y₁ = m(x − x₁), where (x₁, y₁) is the known point.

Example: Line through (3, −1) with gradient 4: y − (−1) = 4(x − 3) → y + 1 = 4x − 12 → y = 4x − 13.

Edexcel exam style

Edexcel frequently tests:

  • "Find the equation of the line perpendicular to L that passes through point P."
  • "Show that two lines are parallel." (Show gradients are equal.)
  • Interpret gradient and intercept in a real-world context (e.g. "what does the gradient represent?").

Common mistakes

  1. Gradient = rise/run, NOT run/rise (mixing up Δy and Δx).
  2. Negative reciprocal: perpendicular gradient of 3 is −1/3, not −3.
  3. Not simplifying: leave fractions in exact form unless told otherwise.
  4. Misreading intercepts from a graph: the y-intercept is where x = 0.

AI-generated · claude-opus-4-7 · v3-edexcel-maths

Practice questions

Try each before peeking at the worked solution.

  1. Question 15 marks

    Find the equation of a line

    (a) A straight line passes through (0, 3) and (4, 11). Find the equation of the line in the form y = mx + c. (3 marks)
    (b) Write down the gradient of a line parallel to y = 5 − 2x. (1 mark)
    (c) Write down the gradient of a line perpendicular to y = 5 − 2x. (1 mark)

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    AI-generated · claude-opus-4-7 · v3-edexcel-maths

  2. Question 25 marks

    Perpendicular line through a point

    Line L has equation 3x + y = 7.

    (a) Write L in the form y = mx + c and state its gradient. (2 marks)
    (b) Find the equation of the line perpendicular to L that passes through (6, 2). (3 marks)

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    AI-generated · claude-opus-4-7 · v3-edexcel-maths

  3. Question 36 marks

    Interpret gradient in context

    A taxi company charges according to the formula C = 2.5d + 3, where C is the total cost in pounds and d is the distance in miles.

    (a) State the value of C when d = 0. What does this represent? (2 marks)
    (b) State the gradient of the line and interpret it in context. (2 marks)
    (c) Calculate the cost of a 12-mile journey. (2 marks)

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    AI-generated · claude-opus-4-7 · v3-edexcel-maths

Flashcards

A9 — Linear graphs: y = mx + c, parallel and perpendicular lines

6-card SR deck for Edexcel GCSE Mathematics (1MA1) topic A9

6 cards · spaced repetition (SM-2)