Roots and indices (laws and fractional indices)
Edexcel 1MA1 tests integer index laws on Foundation, fractional and negative indices on Higher. Higher Paper 1H frequently uses these in non-calculator settings.
Index laws (integer)
For a > 0:
- Multiplication: aᵐ × aⁿ = aᵐ⁺ⁿ.
- Division: aᵐ ÷ aⁿ = aᵐ⁻ⁿ.
- Power of a power: (aᵐ)ⁿ = aᵐⁿ.
- Zero index: a⁰ = 1.
- Negative index: a⁻ⁿ = 1/aⁿ.
Fractional indices (Higher)
- a^(1/2) = √a (the positive square root).
- a^(1/3) = ∛a (the cube root).
- a^(1/n) = ⁿ√a.
- a^(m/n) = (ⁿ√a)ᵐ = (aᵐ)^(1/n).
Practical tip: take the root first (smaller numbers to manipulate), then raise to the power.
Example: 8^(2/3) = (∛8)² = 2² = 4.
Negative fractional indices
a^(−m/n) = 1 / a^(m/n).
Example: 16^(−3/4) = 1 / 16^(3/4) = 1 / (⁴√16)³ = 1 / 2³ = 1/8.
Worked Higher example
Simplify 27^(2/3) × 27^(−1/3).
Method 1 — index law: 27^(2/3 − 1/3) = 27^(1/3) = 3. Method 2 — direct: 27^(2/3) = (∛27)² = 9. 27^(−1/3) = 1/3. Product = 9 × 1/3 = 3.
Combining with surds (touches A23/N8)
Surds are roots that cannot be simplified to integers. Index laws still apply:
- (√a)² = a.
- √a × √a = a.
- √(ab) = √a × √b.
Common Edexcel exam tip
On Paper 1H, "Find the value of 16^(3/4)" — show the root first, then the power: ⁴√16 = 2; 2³ = 8. Each step scores B1 in the mark scheme.
⚠Common mistakes— Common errors
- Treating a⁰ = 0 instead of a⁰ = 1.
- Computing 27^(2/3) by squaring first (27² = 729) then taking cube root (∛729 = 9). This is correct but inefficient — use root first.
- Forgetting the positive root convention: a^(1/2) = +√a only, not ±.
- Confusing (a²)³ = a⁶ with a² × a³ = a⁵.
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