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GCSE/Mathematics/WJEC

R9Percentage change, reverse percentages, problem-solving

Notes

Percentage Change and Reverse Percentages

Percentage Change (Increase / Decrease)

To find the percentage change:

$$\text{Percentage change} = \frac{\text{change}}{\text{original}} \times 100$$

Example: A coat costs £80. In a sale, the price drops to £62. Find the percentage decrease.

$$\text{Change} = 80 - 62 = 18; \quad \text{Percentage decrease} = \frac{18}{80} \times 100 = 22.5%$$

Applying a Percentage Change with a Multiplier

The most efficient method uses a multiplier:

ChangeMultiplier
Increase by 20%$\times 1.20$
Decrease by 15%$\times 0.85$
Increase by 7.5%$\times 1.075$
Decrease by 2%$\times 0.98$

Example: Increase £350 by 18%.

$$350 \times 1.18 = £413$$

Compound Percentage Change

Apply the multiplier repeatedly for each time period.

$$\text{Final value} = \text{Original} \times (\text{multiplier})^n$$

Example: £2000 invested at 4% per annum compound interest for 3 years.

$$2000 \times 1.04^3 = 2000 \times 1.124864 = £2249.73 \text{ (to nearest penny)}$$

Depreciation (e.g. car value decreasing 12% per year):

$$\text{Value after 5 years} = P \times 0.88^5$$

Reverse Percentages (Finding the Original Value)

When you know the value after a percentage change and want the original, divide by the multiplier (do NOT add/subtract the percentage from the final value — a common error!).

$$\text{Original} = \frac{\text{final value}}{\text{multiplier}}$$

Example: A TV costs £510 after a 15% reduction. Find the original price.

Multiplier $= 0.85$ (100% − 15%)

$$\text{Original} = \frac{510}{0.85} = £600$$

Example: After a 20% increase, a salary is £30,000. Find the original salary.

Multiplier $= 1.20$

$$\text{Original} = \frac{30{,}000}{1.20} = £25{,}000$$

WJEC Exam Tips

  • Always identify the original value — it is what you divide into (not the new value).
  • On WJEC Higher papers, reverse percentage and compound interest questions appear frequently.
  • Multiplier method is more efficient than breaking into 10% / 1% steps — use it when marks allow a calculator.
  • For compound interest, distinguish compound (repeated ×) from simple (add the same amount each year).
  • Show the multiplier you are using — it earns M1 even if the final answer is wrong.

AI-generated · claude-opus-4-7 · v3-wjec-maths

Practice questions

Try each before peeking at the worked solution.

  1. Question 12 marks

    Find percentage change

    Question 1 (Calculator, 2 marks)

    A house is bought for £175,000 and sold for £196,000. Calculate the percentage increase.

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    AI-generated · claude-opus-4-7 · v3-wjec-maths

  2. Question 23 marks

    Apply percentage increase/decrease with multiplier

    Question 2 (Calculator, 3 marks)

    (a) Increase £640 by 35%. (1 mark)
    (b) Decrease £840 by 12.5%. (2 marks)

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    AI-generated · claude-opus-4-7 · v3-wjec-maths

  3. Question 33 marks

    Compound interest

    Question 3 (Calculator, 3 marks)

    Amy invests £5000 at 3.2% per annum compound interest. Calculate the value of the investment after 4 years, giving your answer to the nearest penny.

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    AI-generated · claude-opus-4-7 · v3-wjec-maths

  4. Question 43 marks

    Reverse percentage

    Question 4 (Calculator, 3 marks)

    After a 30% discount, a jacket costs £84. Find the original price.

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    AI-generated · claude-opus-4-7 · v3-wjec-maths

  5. Question 54 marks

    Reverse compound percentage

    Question 5 (Calculator, Higher, 4 marks)

    A car depreciates in value by 18% each year. After 3 years, the car is worth £11,000. Find the original price of the car, giving your answer to the nearest £100.

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    AI-generated · claude-opus-4-7 · v3-wjec-maths

  6. Question 64 marks

    Compare simple and compound interest

    Question 6 (Calculator, Higher, 4 marks)

    £8000 is invested for 5 years.

    • Option A: Simple interest at 4% per annum.
    • Option B: Compound interest at 3.5% per annum.

    Which option gives more interest after 5 years? Show your working.

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    AI-generated · claude-opus-4-7 · v3-wjec-maths

Flashcards

R9 — Percentage change, reverse percentages

10-card SR deck for WJEC Eduqas GCSE Maths topic R9

10 cards · spaced repetition (SM-2)