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GCSE/Chemistry/AQA· Higher tier

C4.3Oxidation and reduction in terms of electrons (HT): redox half-equations and identifying species oxidised/reduced

Notes

Redox in terms of electrons (Higher tier)

At Higher tier, oxidation and reduction are defined by electron transfer, not oxygen. This more general definition covers reactions where no oxygen is involved.

The OIL RIG mnemonic

Oxidation Is Loss (of electrons). Reduction Is Gain (of electrons).

A reaction in which one species is oxidised and another reduced is a redox reaction — they always happen together (electrons have to go somewhere).

Worked exampleExample: Mg + Cu²⁺ → Mg²⁺ + Cu

A magnesium strip is dipped into copper sulfate solution. Brown copper deposits onto the magnesium; the blue colour fades.

Split into two half-equations:

  • Mg → Mg²⁺ + 2e⁻ (oxidation: Mg loses electrons)
  • Cu²⁺ + 2e⁻ → Cu (reduction: Cu²⁺ gains electrons)

Adding them: Mg + Cu²⁺ → Mg²⁺ + Cu. Electrons cancel.

Worked exampleExample: 2Na + Cl₂ → 2NaCl

In ionic terms: Na atoms lose electrons; Cl atoms gain.

  • Na → Na⁺ + e⁻ (oxidation)
  • ½Cl₂ + e⁻ → Cl⁻ (reduction; or Cl₂ + 2e⁻ → 2Cl⁻)

Sodium is oxidised; chlorine is reduced.

Displacement reactions are redox

When a more reactive metal displaces a less reactive metal from a salt solution: Zn + CuSO₄ → ZnSO₄ + Cu

The Zn loses 2 e⁻ (oxidised) and Cu²⁺ gains 2 e⁻ (reduced). The sulfate is a spectator ion — it doesn't change.

How to write a half-equation

  1. Identify the species changing (atom → ion or vice versa).
  2. Balance atoms.
  3. Add electrons to balance charge.

Example: Cl₂ → 2Cl⁻ needs 2 electrons on the LEFT to balance charge: Cl₂ + 2e⁻ → 2Cl⁻.

Worked exampleWorked example: identifying redox

In Fe + CuSO₄ → FeSO₄ + Cu, identify the species oxidised and reduced.

  • Fe(0) → Fe²⁺(+2): lost 2 e⁻ → oxidised.
  • Cu²⁺(+2) → Cu(0): gained 2 e⁻ → reduced.

Common mistakes

  • Forgetting OIL RIG. Oxidation = lose; Reduction = gain.
  • Putting electrons on the wrong side. They go on the same side as the more positive species (so the equation balances).
  • Not balancing charge. Charges and atoms both must balance.
  • Saying "Cu²⁺ is oxidised" — Cu²⁺ gains electrons to become Cu, so it's reduced.

Links

Builds on C4.1 (oxygen-based redox). Used heavily in C4.9–C4.12 (electrolysis half-equations) and C8.5 (reactions used in tests).

AI-generated · claude-opus-4-7 · v3-deep-chemistry

Practice questions

Try each before peeking at the worked solution.

  1. Question 12 marks

    Define OIL RIG (H)

    (H1) State what OIL RIG stands for.

    [Higher — 2 marks]

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    AI-generated · claude-opus-4-7 · v3-deep-chemistry

  2. Question 22 marks

    Half-equation Mg (H)

    (H2) Write the half-equation for magnesium being oxidised to magnesium ions.

    [Higher — 2 marks]

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    AI-generated · claude-opus-4-7 · v3-deep-chemistry

  3. Question 32 marks

    Half-equation Cu²⁺ (H)

    (H3) Write the half-equation for the reduction of copper(II) ions.

    [Higher — 2 marks]

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    AI-generated · claude-opus-4-7 · v3-deep-chemistry

  4. Question 43 marks

    Identify redox (H)

    (H4) In Zn + CuSO₄ → ZnSO₄ + Cu, identify (a) the species oxidised, (b) the species reduced, (c) the spectator ion.

    [Higher — 3 marks]

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    AI-generated · claude-opus-4-7 · v3-deep-chemistry

  5. Question 52 marks

    Half-equation Cl (H)

    (H5) Write the half-equation for chlorine molecules forming chloride ions.

    [Higher — 2 marks]

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    AI-generated · claude-opus-4-7 · v3-deep-chemistry

  6. Question 62 marks

    Combine half-eqns (H)

    (H6) Combine Mg → Mg²⁺ + 2e⁻ and Cl₂ + 2e⁻ → 2Cl⁻ into the overall ionic equation.

    [Higher — 2 marks]

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    AI-generated · claude-opus-4-7 · v3-deep-chemistry

  7. Question 73 marks

    Why displacement is redox (H)

    (H7) Explain why the reaction Fe + Cu²⁺ → Fe²⁺ + Cu is described as a redox reaction.

    [Higher — 3 marks]

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    AI-generated · claude-opus-4-7 · v3-deep-chemistry

Flashcards

C4.3 — Redox in terms of electrons (HT)

10-card HT deck on OIL RIG, half-equations and identifying redox processes.

10 cards · spaced repetition (SM-2)