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GCSE/Mathematics/AQA

R14Interpret gradient as rate of change; proportion graphs

Notes

Gradient as a rate of change; proportion graphs

A gradient on a graph is more than a number — it carries physical meaning. In real-world contexts, gradient = "how much y changes per unit increase in x".

Gradient = rate of change

For a straight-line graph, gradient = (rise)/(run) = Δy/Δx. The units of gradient are (units of y)/(units of x).

GraphGradient meaning
Distance–timespeed (m/s, km/h)
Velocity–timeacceleration (m/s²)
Cost–quantityunit price (£ per item)
Conversion graphexchange rate
Mass–volumedensity

Worked example: a distance–time graph passes through (0, 0) and (4, 80). Gradient = 80/4 = 20 km/h — the speed.

Proportion graphs

A direct proportion (y ∝ x) graphs as a straight line through the origin. The gradient = the constant of proportionality k.

Worked example: a graph of cost (£) vs litres of fuel passes through (0, 0) and (10, 14). Gradient = 14/10 = £1.40 per litre. Equation: C = 1.4ℓ.

Negative gradient

A negative gradient means y decreases as x increases.

Worked example: a tank empties uniformly. Volume–time graph passes through (0, 50) and (10, 30). Gradient = (30 − 50)/(10 − 0) = −2 (litres per minute).

Reading gradient between two points

Gradient = (y₂ − y₁) / (x₂ − x₁).

Common mistakes

  1. Forgetting units — gradient has units; state them in context.
  2. Confusing rise and run — rise is vertical change (y), run is horizontal (x).
  3. Reading axes incorrectly — check the scale of each axis, not just the squares.
  4. Negative gradient sign error — y decreasing → negative gradient.
  5. Treating proportion graphs that don't pass through origin as direct — check it does pass through (0, 0).

Try thisQuick check

A line passes through (3, 7) and (8, 22). Find the gradient and interpret as a rate.

  • (22 − 7)/(8 − 3) = 15/5 = 3 — y increases by 3 per unit increase in x.

AI-generated · claude-opus-4-7 · v3-deep-ratio

Practice questions

Try each before peeking at the worked solution.

  1. Question 12 marks

    Gradient between two points

    (F1) Find the gradient of the line through (1, 5) and (4, 14).

    [Foundation tier]

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  2. Question 22 marks

    Gradient = speed

    (F2) A distance–time graph for a cyclist is a straight line through (0, 0) and (3, 36) where time is in hours and distance in km. Find the cyclist\u2019s speed.

    [Foundation tier]

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    AI-generated · claude-opus-4-7 · v3-deep-ratio

  3. Question 32 marks

    Negative gradient

    (F3) A water tank empties uniformly. The graph of volume V (in litres) against time t (in minutes) passes through (0, 80) and (10, 60). Find the gradient and interpret it.

    [Foundation tier]

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    AI-generated · claude-opus-4-7 · v3-deep-ratio

  4. Question 43 marks

    Conversion graph

    (F/H4) A conversion graph between £ and $ is a straight line through (0, 0) and (50, 65). (a) State the gradient. (b) State the exchange rate.

    [Crossover tier]

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  5. Question 52 marks

    Density from graph

    (F/H5) A graph of mass (g) vs volume (cm³) is a straight line through (0, 0) and (5, 40). State the density of the substance.

    [Crossover tier]

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  6. Question 64 marks

    Acceleration from velocity-time

    (H6) A velocity–time graph rises from (0, 4) to (10, 24) where v is in m/s and t in s. (a) Find the acceleration. (b) Use a v–t formula to find v at t = 6.

    [Higher tier]

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  7. Question 74 marks

    Identify proportion graph

    (H7) Three lines are drawn:

    • Line A: y = 3x
    • Line B: y = 2x + 5
    • Line C: y = 0.5x − 1

    (a) Which represents direct proportion? Justify.
    (b) State the gradient and y-intercept of line B.

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Flashcards

R14 — Interpret gradient as rate of change; proportion graphs

12-card SR deck for AQA GCSE Maths topic R14

12 cards · spaced repetition (SM-2)