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GCSE/Mathematics/CCEA

R3Percentages: percentage change, reverse percentages, compound interest

Notes

Percentages — percentage change, reverse and compound interest

Percentage change

Percentage increase/decrease = (change ÷ original) × 100.

Example: A price rises from £48 to £60. Change = 60 − 48 = 12. Percentage increase = (12 ÷ 48) × 100 = 25%.

Using a multiplier (more efficient):

  • Increase of 30%: multiply by 1.30.
  • Decrease of 15%: multiply by 0.85.
  • Combined: original × multiplier → new value.

Example: A £250 jacket is reduced by 20% in a sale. Find the sale price. Sale price = 250 × 0.80 = £200.

Reverse percentages

When you know the amount AFTER a percentage change and need to find the ORIGINAL, use reverse percentages (work backwards from the multiplier).

Example: After a 30% increase, a salary is £26,000. What was the original salary? The multiplier for +30% is 1.30. Original = 26,000 ÷ 1.30 = £20,000.

Common mistake: students subtract 30% from £26,000 and get £18,200. This is wrong because 30% of the NEW salary, not the original.

Compound interest

Compound interest is calculated on the accumulated balance (including previously earned interest), not just the original amount.

Formula: A = P × (1 + r/100)ⁿ

Where A = final amount, P = principal, r = rate per period (%), n = number of periods.

Example: £2,000 is invested at 4% per year compound interest for 5 years. A = 2000 × (1.04)⁵ = 2000 × 1.2166... = £2433.31 (to the nearest penny).

Simple interest (for contrast): interest is calculated on the original principal only. Simple interest = P × r × n / 100.

Repeated percentage change

The compound interest formula also applies to population growth, depreciation, and inflation:

Depreciation: A car worth £12,000 depreciates by 15% per year. Value after 4 years: V = 12,000 × (0.85)⁴ = 12,000 × 0.5220... ≈ £6,264.

Combined percentage changes: an 8% increase followed by a 5% decrease. Overall multiplier = 1.08 × 0.95 = 1.026 → 2.6% overall increase (not 3%).

CCEA examiner style

CCEA Paper 2 frequently presents percentage problems in context (shop discounts, salary changes, population growth, VAT). Identify the correct base before calculating.

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Practice questions

Try each before peeking at the worked solution.

  1. Question 15 marks

    Percentage change

    (a) A coat costs £85. It is reduced by 40% in a sale. Find the sale price. (2 marks)
    (b) A house was bought for £140,000 and sold for £175,000. Calculate the percentage profit. (3 marks)

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  2. Question 23 marks

    Reverse percentage

    After a price increase of 20%, a television costs £480. Calculate the original price.

    [3 marks]

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  3. Question 33 marks

    Compound interest

    £5,000 is invested at a compound interest rate of 3.5% per annum. Calculate the value of the investment after 6 years. Give your answer to the nearest penny.

    [3 marks]

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  4. Question 44 marks

    Depreciation

    A car is purchased for £18,500. It depreciates in value by 18% in the first year and 12% in each subsequent year. Calculate its value at the end of 4 years. Give your answer to the nearest pound.

    [4 marks]

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  5. Question 53 marks

    Combined percentage changes

    An item has its price increased by 15%, then decreased by 10%. A student says: "The overall change is a 5% increase." Is the student correct? Justify your answer with a calculation.

    [3 marks]

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Flashcards

R3 — Percentages: percentage change, reverse percentages and compound interest

8-card SR deck for CCEA GCSE Mathematics (GMV11) topic R3

8 cards · spaced repetition (SM-2)