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GCSE/Mathematics/WJEC· Higher tier

N7Calculate with roots and integer indices; fractional indices

Notes

Indices and roots

Examined every WJEC paper. Foundation handles integer powers; Intermediate adds the laws; Higher tackles fractional and negative indices and surd manipulation.

Index laws

For positive integers a, b and any base x ≠ 0:

  • x^a × x^b = x^(a+b)
  • x^a ÷ x^b = x^(a−b)
  • (x^a)^b = x^(a×b)
  • (xy)^a = x^a × y^a
  • x^0 = 1

Negative indices

x^(−n) = 1 / x^n.

  • 2^(−3) = 1 / 2^3 = 1/8
  • (3/4)^(−1) = 4/3 (reciprocal)

Fractional indices

  • x^(1/n) = nth root of x. So 27^(1/3) = ∛27 = 3.
  • x^(m/n) = (nth root of x)^m. So 8^(2/3) = (∛8)^2 = 2^2 = 4.

The order is reversible — root first or power first — but rooting first usually gives smaller numbers.

Roots and surds

  • √(ab) = √a × √b
  • √(a/b) = √a / √b
  • a√b + c√b = (a + c)√b (collecting "like surds")

Simplifying surds — find a square factor

√50 = √(25 × 2) = 5√2. WJEC always wants surd form a√b with smallest b.

Rationalising the denominator

To rationalise k / √a: multiply top and bottom by √a.

  • 6 / √2 = 6√2 / 2 = 3√2.

For binomial denominators (Higher only): k / (a + √b) → multiply by conjugate (a − √b).

WJEC exam tip

When using fractional indices, calculate the root first, then the power — keeps numbers small. Always show the explicit step (e.g. "8^(2/3) = (∛8)^2") for the M1.

AI-generated · claude-opus-4-7 · v3-wjec-maths-leaves

Practice questions

Try each before peeking at the worked solution.

  1. Question 15 marks

    Apply index laws (integer)

    WJEC Unit 1 (Non-calculator) — Foundation

    Simplify, leaving each answer as a single power:

    (a) 5^4 × 5^7 (1 mark)
    (b) 8^9 ÷ 8^4 (1 mark)
    (c) (3^2)^5 (1 mark)
    (d) 7^6 × 7^(−4) (2 marks)

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-wjec-maths-leaves

  2. Question 25 marks

    Negative and fractional indices

    WJEC Unit 1 (Non-calculator) — Intermediate

    Evaluate without a calculator:

    (a) 4^(−2) (1 mark)
    (b) 25^(1/2) (1 mark)
    (c) 27^(2/3) (3 marks)

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-wjec-maths-leaves

  3. Question 36 marks

    Surd simplification and rationalising

    WJEC Unit 1 (Non-calculator) — Higher

    (a) Simplify √72. (2 marks)
    (b) Rationalise the denominator and simplify: 10 / √5. (2 marks)
    (c) Show that (3 + √2)(3 − √2) is an integer and find its value. (2 marks)

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-wjec-maths-leaves

Flashcards

N7 — Calculate with roots and integer indices; fractional indices

7-card SR deck for WJEC GCSE Mathematics — Leaves Batch 2 topic N7

7 cards · spaced repetition (SM-2)