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GCSE/Physics/AQA

P5.13Required practical 7 — investigating acceleration: using a trolley/light gates or data-logger to test F = ma and verify the relationship

Notes

Required practical 7 — Investigating acceleration

Test Newton's second law $F = ma$ by varying force on a constant-mass trolley, or varying mass with a constant force. Plot graphs to confirm linear relationships.

Apparatus

  • Dynamics trolley.
  • Bench (preferably tilted slightly to compensate for friction, or on a smooth track).
  • String over a pulley.
  • Hanging masses.
  • Light gates connected to a data-logger (or ticker timer / motion sensor).

Method — Investigation 1: F vs a

  1. Set up trolley with light gates spaced at fixed distance apart.
  2. Total mass on the system (trolley + hanger + masses) kept constant by transferring masses between trolley and hanger.
  3. Hang one slotted mass; release trolley. Record acceleration from light gates.
  4. Move masses one at a time from trolley to hanger (increasing accelerating force).
  5. Plot $a$ (y-axis) vs $F$ (x-axis). Should be a straight line through the origin: $a \propto F$ for constant mass.

Method — Investigation 2: m vs a

  1. Same setup but keep the hanging mass (and so $F$) constant.
  2. Add masses to the trolley to change total $m$.
  3. Record $a$ for each total mass.
  4. Plot $a$ vs $1/m$. Should be a straight line: $a \propto 1/m$ for constant force.

Why transfer masses?

When measuring $a$ vs $F$, total mass of the system (trolley + hanger) must remain constant. If you simply add masses to the hanger, you'd also be adding mass to the system. By transferring them, you increase $F$ without changing total $m$.

Sources of error

  • Friction — slows the trolley; offset by tilting the bench until trolley moves at constant v with no force, OR by including friction force in calculations.
  • Light gate placement — must be perpendicular to motion, accurately measured separation.
  • Air resistance — small at low speeds.
  • Pulley friction — assumed negligible.

Worked example

In Investigation 1, with total mass 1.0 kg, hanging 0.20 N gives a = 0.20 m/s². Verify $F = ma$.

  • F = ma = 1.0 × 0.20 = 0.20 N. ✓

Common mistakes

  1. Forgetting to keep total mass constant when varying F.
  2. Using the trolley's mass alone — must include hanger and masses on it.
  3. Not zeroing for friction — graph won't pass through origin.
  4. Confusing the force on the system (mg of hanger) with the weight on the trolley alone.

AI-generated · claude-opus-4-7 · v3-deep-physics

Practice questions

Try each before peeking at the worked solution.

  1. Question 13 marks

    Apparatus

    Name three pieces of apparatus needed for the F = ma practical.

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    AI-generated · claude-opus-4-7 · v3-deep-physics

  2. Question 22 marks

    Why transfer masses

    When investigating a vs F, why are masses transferred between trolley and hanger rather than just added to the hanger?

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    AI-generated · claude-opus-4-7 · v3-deep-physics

  3. Question 32 marks

    Plot for a ∝ F

    What graph would confirm that a is proportional to F (at constant m)?

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    AI-generated · claude-opus-4-7 · v3-deep-physics

  4. Question 42 marks

    Plot for a ∝ 1/m

    What graph would confirm a is proportional to 1/m (at constant F)?

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    AI-generated · claude-opus-4-7 · v3-deep-physics

  5. Question 52 marks

    Reduce friction error

    How can the bench be set up to compensate for friction?

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    AI-generated · claude-opus-4-7 · v3-deep-physics

  6. Question 63 marks

    Verify F = ma

    In a trial, total mass is 0.80 kg, hanging weight is 0.50 N, measured a = 0.60 m/s². Compare with theoretical.

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    AI-generated · claude-opus-4-7 · v3-deep-physics

Flashcards

P5.13 — Required practical 7 — investigating acceleration

10-card SR deck for AQA GCSE Physics topic P5.13

10 cards · spaced repetition (SM-2)