Required practical 7 — Investigating acceleration
Test Newton's second law $F = ma$ by varying force on a constant-mass trolley, or varying mass with a constant force. Plot graphs to confirm linear relationships.
Apparatus
- Dynamics trolley.
- Bench (preferably tilted slightly to compensate for friction, or on a smooth track).
- String over a pulley.
- Hanging masses.
- Light gates connected to a data-logger (or ticker timer / motion sensor).
Method — Investigation 1: F vs a
- Set up trolley with light gates spaced at fixed distance apart.
- Total mass on the system (trolley + hanger + masses) kept constant by transferring masses between trolley and hanger.
- Hang one slotted mass; release trolley. Record acceleration from light gates.
- Move masses one at a time from trolley to hanger (increasing accelerating force).
- Plot $a$ (y-axis) vs $F$ (x-axis). Should be a straight line through the origin: $a \propto F$ for constant mass.
Method — Investigation 2: m vs a
- Same setup but keep the hanging mass (and so $F$) constant.
- Add masses to the trolley to change total $m$.
- Record $a$ for each total mass.
- Plot $a$ vs $1/m$. Should be a straight line: $a \propto 1/m$ for constant force.
Why transfer masses?
When measuring $a$ vs $F$, total mass of the system (trolley + hanger) must remain constant. If you simply add masses to the hanger, you'd also be adding mass to the system. By transferring them, you increase $F$ without changing total $m$.
Sources of error
- Friction — slows the trolley; offset by tilting the bench until trolley moves at constant v with no force, OR by including friction force in calculations.
- Light gate placement — must be perpendicular to motion, accurately measured separation.
- Air resistance — small at low speeds.
- Pulley friction — assumed negligible.
✦Worked example
In Investigation 1, with total mass 1.0 kg, hanging 0.20 N gives a = 0.20 m/s². Verify $F = ma$.
- F = ma = 1.0 × 0.20 = 0.20 N. ✓
⚠Common mistakes
- Forgetting to keep total mass constant when varying F.
- Using the trolley's mass alone — must include hanger and masses on it.
- Not zeroing for friction — graph won't pass through origin.
- Confusing the force on the system (mg of hanger) with the weight on the trolley alone.
AI-generated · claude-opus-4-7 · v3-deep-physics