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Notes

Coordinates in all four quadrants

Coordinates are the bridge between geometry and algebra. The Cartesian plane has two perpendicular axes (the x-axis and y-axis) crossing at the origin (0, 0). Every point is described by an ordered pair (x, y) — x first (horizontal), y second (vertical).

The four quadrants

Numbered anti-clockwise starting top-right:

  • Q1: x > 0, y > 0 (top-right) — e.g. (3, 4)
  • Q2: x < 0, y > 0 (top-left) — e.g. (-3, 4)
  • Q3: x < 0, y < 0 (bottom-left) — e.g. (-3, -4)
  • Q4: x > 0, y < 0 (bottom-right) — e.g. (3, -4)

Points on the axes themselves belong to no quadrant.

Plotting and reading

Always count along the x-axis first, then up/down the y-axis. Make sure your plot lands at a crossing point of grid lines, not in the middle of a square.

Distance between two points

Given A(x₁, y₁) and B(x₂, y₂), the distance is from Pythagoras' theorem:

AB = √((x₂ - x₁)² + (y₂ - y₁)²)

Example: distance between A(1, 2) and B(4, 6). Differences: 4 - 1 = 3, 6 - 2 = 4. Distance = √(9 + 16) = √25 = 5.

Midpoint of a segment

Average the coordinates: M = ((x₁ + x₂)/2, (y₁ + y₂)/2).

Example: midpoint of (1, 2) and (5, 8) is ((1 + 5)/2, (2 + 8)/2) = (3, 5).

Gradient between two points

gradient = (y₂ - y₁)/(x₂ - x₁) — the rise over run.

Example: from (1, 2) to (4, 8): gradient = (8 - 2)/(4 - 1) = 6/3 = 2. The line goes up 2 units for every 1 unit right.

Worked exampleWorked example — combining

A is (-2, 3); B is (4, -5). Find (i) midpoint, (ii) length AB, (iii) gradient AB.

  • Midpoint: ((-2 + 4)/2, (3 + -5)/2) = (1, -1).
  • Length: √((4 - (-2))² + (-5 - 3)²) = √(36 + 64) = √100 = 10.
  • Gradient: (-5 - 3)/(4 - (-2)) = -8/6 = -4/3.

Common mistakesCommon mistakes (examiner traps)

  1. Reversing x and y. "Along the corridor and up the stairs" — x first, y second.
  2. Sign errors with negatives. (4 - (-2)) = 6, not 2. Use brackets when subtracting negatives.
  3. Forgetting the square root in the distance formula. The formula gives distance squared until you root it.
  4. Using midpoint = (x₂ - x₁)/2. That's half the run, not a midpoint. Use the SUM, divided by 2.
  5. Confusing rise/run. The gradient is vertical change ÷ horizontal change, in that order.

Try thisQuick check

(a) Midpoint of (-3, 7) and (5, 1): ((−3 + 5)/2, (7 + 1)/2) = (1, 4). (b) Distance between (0, 0) and (5, 12): √(25 + 144) = √169 = 13.

AI-generated · claude-opus-4-7 · v3-deep-algebra

Practice questions

Try each before peeking at the worked solution.

  1. Question 14 marks

    Identify quadrant

    (F1) State the quadrant containing each point.
    (a) (-2, 5)
    (b) (4, -1)
    (c) (-3, -3)
    (d) (6, 2)

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    AI-generated · claude-opus-4-7 · v3-deep-algebra

  2. Question 23 marks

    Read coordinates from a description

    (F2) A point lies on the y-axis, 4 units below the origin. Write its coordinates.

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    AI-generated · claude-opus-4-7 · v3-deep-algebra

  3. Question 33 marks

    Midpoint of two points

    (F3) Find the midpoint of A(-2, 5) and B(6, -1).

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    AI-generated · claude-opus-4-7 · v3-deep-algebra

  4. Question 43 marks

    Distance between points (positive coordinates)

    (F/H4) Find the distance from (1, 2) to (7, 10). Give your answer to 1 d.p.

    [Foundation/Higher crossover]

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    AI-generated · claude-opus-4-7 · v3-deep-algebra

  5. Question 53 marks

    Distance with negative coordinates

    (H5) Find the distance from A(-3, 4) to B(5, -2).

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    AI-generated · claude-opus-4-7 · v3-deep-algebra

  6. Question 63 marks

    Gradient between two points

    (H6) Find the gradient of the line through (-1, 4) and (3, -8).

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    AI-generated · claude-opus-4-7 · v3-deep-algebra

  7. Question 74 marks

    Find a missing endpoint given midpoint

    (H7) The midpoint of AB is (2, 5). A is (-1, 3). Find the coordinates of B.

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    AI-generated · claude-opus-4-7 · v3-deep-algebra

Flashcards

A8 — Coordinates

10-card SR deck for AQA GCSE Maths topic A8

10 cards · spaced repetition (SM-2)