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GCSE/Mathematics/WJEC· Higher tier

A7Interpret expressions as functions; inverse and composite functions

Notes

Functions, inverses and composites

Functions appear on WJEC Higher Unit 1 and Unit 2. The notation looks intimidating but the rules are mechanical.

Function notation

f(x) = 3x − 2 is a rule: input x, multiply by 3, subtract 2. To evaluate f(5): replace x with 5 → f(5) = 3(5) − 2 = 13.

You may see g(x), h(x) used alongside f(x) in the same question — each is a separate rule.

Inverse functions

The inverse f⁻¹(x) reverses f. Method:

  1. Write y = f(x).
  2. Swap x and y.
  3. Solve for y. That expression is f⁻¹(x).

Example: f(x) = 3x − 2.

  • y = 3x − 2
  • Swap: x = 3y − 2
  • Solve: y = (x + 2) / 3
  • f⁻¹(x) = (x + 2) / 3.

Check: f⁻¹(13) = (13 + 2) / 3 = 5 ✓ (the original input).

Composite functions

fg(x) means apply g first, then f. So fg(x) = f(g(x)). Notation order is RIGHT-TO-LEFT.

Example: f(x) = 3x − 2, g(x) = x + 4.

  • fg(x) = f(x + 4) = 3(x + 4) − 2 = 3x + 12 − 2 = 3x + 10.
  • gf(x) = g(3x − 2) = (3x − 2) + 4 = 3x + 2.

Notice fg ≠ gf in general.

Domain and range (informal)

WJEC may ask for the domain (set of allowed inputs) and range (set of possible outputs). For f(x) = √x the domain is x ≥ 0 since you cannot square-root a negative number.

WJEC exam tip

For composites, write the working line by line: "g(x) = …, then f(g(x)) = …". The first substitution earns M1, the simplification earns A1. Don't skip steps — examiners will not award the A1 if you only show the final answer.

AI-generated · claude-opus-4-7 · v3-wjec-maths-leaves

Practice questions

Try each before peeking at the worked solution.

  1. Question 16 marks

    Evaluate and find inverse

    WJEC Unit 1 (Non-calculator) — Higher

    f(x) = 4x − 7.

    (a) Evaluate f(3). (1 mark)
    (b) Find an expression for f⁻¹(x). (2 marks)
    (c) Solve f(x) = f⁻¹(x). (3 marks)

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-wjec-maths-leaves

  2. Question 27 marks

    Composite function evaluation

    WJEC Unit 2 (Calculator) — Higher

    f(x) = x² + 1 and g(x) = 2x − 3.

    (a) Find fg(4). (2 marks)
    (b) Find an expression for gf(x). (2 marks)
    (c) Solve fg(x) = 26. (3 marks)

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-wjec-maths-leaves

  3. Question 35 marks

    Determine an unknown via composition

    WJEC Unit 1 (Non-calculator) — Higher

    f(x) = 3x + a, where a is a constant. Given that f(2) = 11:

    (a) Find a. (2 marks)
    (b) Using your value of a, find f⁻¹(x). (2 marks)
    (c) State a value of x for which f⁻¹(x) is undefined, or explain that f⁻¹ is defined for all real x. (1 mark)

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-wjec-maths-leaves

  4. Question 46 marks

    Evaluate and find inverse

    WJEC Unit 1 (Non-calculator) — Higher

    f(x) = 4x − 7.

    (a) Evaluate f(3). (1 mark)
    (b) Find an expression for f⁻¹(x). (2 marks)
    (c) Solve f(x) = f⁻¹(x). (3 marks)

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-wjec-maths-leaves

  5. Question 57 marks

    Composite function evaluation

    WJEC Unit 2 (Calculator) — Higher

    f(x) = x² + 1 and g(x) = 2x − 3.

    (a) Find fg(4). (2 marks)
    (b) Find an expression for gf(x). (2 marks)
    (c) Solve fg(x) = 26. (3 marks)

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-wjec-maths-leaves

  6. Question 65 marks

    Determine an unknown via composition

    WJEC Unit 1 (Non-calculator) — Higher

    f(x) = 3x + a, where a is a constant. Given that f(2) = 11:

    (a) Find a. (2 marks)
    (b) Using your value of a, find f⁻¹(x). (2 marks)
    (c) State a value of x for which f⁻¹(x) is undefined, or explain that f⁻¹ is defined for all real x. (1 mark)

    Ask AI about this

    AI-generated · claude-opus-4-7 · v3-wjec-maths-leaves

Flashcards

A7 — Interpret expressions as functions; inverse and composite functions

7-card SR deck for WJEC GCSE Mathematics (leaves batch 3) topic A7

7 cards · spaced repetition (SM-2)