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GCSE/Mathematics/WJEC

A9Plot linear graphs; y = mx + c; parallel and perpendicular lines

Notes

Linear Graphs — y = mx + c

The Equation of a Straight Line

Every straight-line graph can be written as:

$$y = mx + c$$

  • $m$ is the gradient (slope) — how steep the line is.
  • $c$ is the y-intercept — where the line crosses the y-axis.

Example: For $y = 3x - 2$, the gradient is $3$ and the y-intercept is $(0, -2)$.

Calculating the Gradient

$$m = \frac{\text{rise}}{\text{run}} = \frac{\text{change in } y}{\text{change in } x} = \frac{y_2 - y_1}{x_2 - x_1}$$

Example: Find the gradient of the line through $(1, 4)$ and $(5, 12)$.

$$m = \frac{12 - 4}{5 - 1} = \frac{8}{4} = 2$$

Sign of gradient:

  • Positive gradient → line goes up from left to right.
  • Negative gradient → line goes down from left to right.
  • Zero gradient → horizontal line.
  • Undefined gradient → vertical line.

Finding the Equation of a Line

Given gradient $m$ and a point $(x_1, y_1)$:

Use $y - y_1 = m(x - x_1)$ and rearrange to $y = mx + c$.

Example: Gradient $= 3$, passes through $(2, 7)$.

$$y - 7 = 3(x - 2) \implies y = 3x - 6 + 7 = 3x + 1$$

Parallel Lines

Parallel lines have the same gradient.

  • $y = 2x + 5$ and $y = 2x - 3$ are parallel (both have $m = 2$).
  • A line parallel to $y = 4x - 1$ through $(0, 3)$ is $y = 4x + 3$.

Perpendicular Lines

Perpendicular lines have gradients whose product is $-1$:

$$m_1 \times m_2 = -1 \quad \Longleftrightarrow \quad m_2 = -\frac{1}{m_1}$$

This is called the negative reciprocal.

Example: A line has gradient $\frac{2}{3}$. A perpendicular line has gradient $-\frac{3}{2}$.

Example: Find the equation of the line perpendicular to $y = 5x - 4$ passing through $(5, 3)$.

Gradient of given line: $5$. Perpendicular gradient: $-\frac{1}{5}$.

$$y - 3 = -\frac{1}{5}(x - 5) \implies y = -\frac{1}{5}x + 1 + 3 = -\frac{1}{5}x + 4$$

Drawing a Straight-Line Graph

  1. Choose 3 values of $x$, calculate $y$.
  2. Plot the three points.
  3. Draw a straight line through them.

WJEC Exam Tips

  • Always label axes and the equation of the line.
  • To find where two lines intersect, solve simultaneously.
  • "Show the gradient" means draw a right-angled triangle on your line and calculate rise ÷ run.
  • Watch for lines written as $ax + by = c$ — rearrange to $y = mx + c$ first.

AI-generated · claude-opus-4-7 · v3-wjec-maths

Practice questions

Try each before peeking at the worked solution.

  1. Question 12 marks

    Identify gradient and y-intercept

    Question 1 (2 marks)

    Write down the gradient and y-intercept of the line $y = -3x + 7$.

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  2. Question 23 marks

    Calculate gradient from two points

    Question 2 (Non-calculator, 3 marks)

    Find the equation of the straight line passing through $(2, 3)$ and $(6, 11)$.

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  3. Question 33 marks

    Parallel line equation

    Question 3 (Non-calculator, 3 marks)

    Find the equation of the line parallel to $y = 4x - 3$ that passes through the point $(1, 6)$.

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  4. Question 44 marks

    Perpendicular line equation

    Question 4 (Non-calculator, Higher, 4 marks)

    The line $L$ has equation $3x + y = 10$.

    (a) Write $L$ in the form $y = mx + c$. (1 mark)
    (b) Find the equation of the line perpendicular to $L$ that passes through $(6, 1)$. (3 marks)

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  5. Question 54 marks

    Intersection of two lines

    Question 5 (Non-calculator, Higher, 4 marks)

    Find the coordinates of the point of intersection of the lines $y = 2x + 1$ and $y = -x + 7$.

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  6. Question 62 marks

    Interpret gradient in context

    Question 6 (Calculator, 2 marks)

    A taxi costs £2.50 plus £1.80 per km. Write a formula for the total cost $C$ (in £) for a journey of $d$ km. State what the gradient and y-intercept represent in context.

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Flashcards

A9 — Linear graphs; y = mx + c; parallel and perpendicular lines

10-card SR deck for WJEC Eduqas GCSE Maths topic A9

10 cards · spaced repetition (SM-2)