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GCSE/Mathematics/OCR

A15Calculate or estimate gradients and areas under graphs; interpret in context

Notes

Gradients and areas under graphs

OCR J560 Higher (J560/04–06) tests numerical estimation of gradients of curves and areas under curves, with interpretation in context. This is the GCSE bridge to integration and differentiation.

Estimating a gradient at a point

(See R15 for the tangent method.) Draw a tangent at the point of interest, pick two clear points on the tangent, and compute (Δy)/(Δx). Quote the answer with units appropriate to the axes.

Estimating an area under a curve

For a straight-line graph, area = a triangle, rectangle, or trapezium.

For a curve, use the trapezium rule: split the area into vertical strips of equal width h. Each strip is approximated by a trapezium. Sum the areas.

Trapezium rule (n strips of width h): Area ≈ (h/2) × [y₀ + 2(y₁ + y₂ + ... + y_{n−1}) + y_n]

Where y₀, y₁, ..., y_n are the y-values at the strip boundaries.

Worked exampleWorked example — trapezium rule

Estimate the area under y = x² between x = 0 and x = 4 using 4 strips of width 1.

Boundaries: x = 0, 1, 2, 3, 4 with y = 0, 1, 4, 9, 16.

Area ≈ (1/2) × [0 + 2(1 + 4 + 9) + 16] = (1/2) × [0 + 28 + 16] = (1/2) × 44 = 22.

The exact area is 64/3 ≈ 21.33, so the trapezium rule overestimates here (curve is below the chords).

Interpretation

On a speed–time graph, area = distance. On a flow rate–time graph (rate of water in litres/s vs time), area = total volume. On a current–time graph (amperes vs time), area = total charge in coulombs.

Over- vs under-estimate

The trapezium rule:

  • Overestimates when the curve is concave up (cup-shaped, like y = x²).
  • Underestimates when the curve is concave down (cap-shaped).

OCR Higher questions sometimes ask you to state which.

OCR mark scheme conventions

  • M1 for splitting the region into trapezia of equal width.
  • M1 for substituting y-values correctly.
  • A1 for the numerical area.
  • B1 for the contextual interpretation with units (e.g. "the total distance is 22 m").

Common mistakes

  1. Using unequal strip widths without adjusting the formula.
  2. Forgetting the factor 1/2 in the trapezium rule.
  3. Doubling the endpoint y-values (only the inner ones get doubled).
  4. Reporting an area without context or units.

AI-generated · claude-opus-4-7 · v3-ocr-maths-leaves

Practice questions

Try each before peeking at the worked solution.

  1. Question 13 marks

    Trapezium rule basic

    OCR J560/05 — Higher (calculator)

    A speed–time graph passes through the points (0, 0), (2, 5), (4, 12), (6, 18), (8, 20), where time is in seconds and speed in m/s.

    Use the trapezium rule with strip width 2 to estimate the distance travelled in the first 8 seconds. [3]

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    AI-generated · claude-opus-4-7 · v3-ocr-maths-leaves

  2. Question 24 marks

    Gradient and interpretation

    OCR J560/04 — Higher (non-calculator)

    A graph plots volume of water V (litres) against time t (s). At t = 4, a tangent has been drawn passing through (0, 2) and (8, 18).

    (a) Find the gradient of the tangent. [2]
    (b) Interpret this gradient in context, with units. [2]

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    AI-generated · claude-opus-4-7 · v3-ocr-maths-leaves

  3. Question 32 marks

    Over- or under-estimate?

    OCR J560/06 — Higher (calculator)

    A trapezium rule estimate has been used to find the area under a curve y = f(x) between x = 0 and x = 6. The curve has y'' > 0 throughout the interval (i.e. it is concave up).

    (a) State whether the trapezium rule gives an overestimate or an underestimate. [1]
    (b) Explain how this could be made more accurate. [1]

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    AI-generated · claude-opus-4-7 · v3-ocr-maths-leaves

Flashcards

A15 — Calculate or estimate gradients and areas under graphs; interpret in context

7-card SR deck for OCR GCSE Mathematics J560 (leaf top-up — batch 4) topic A15

7 cards · spaced repetition (SM-2)