nth term of sequences
Sequences appear on all OCR J560 papers. The nth term formula allows any term to be found directly. Linear nth terms are Foundation and Higher; quadratic nth terms (an² + bn + c) are Higher-tier only.
Linear (arithmetic) sequences
A linear sequence has a constant difference between terms.
nth term = dn + c where d = common difference.
Method:
- Find the common difference d (nth term coefficient).
- Write dn. Compare the sequence with dn to find c.
Example: 5, 8, 11, 14, ...
- Difference = 3 → coefficient is 3.
- Sequence of 3n: 3, 6, 9, 12, ...
- The given sequence is 2 more than 3n at each position.
- nth term = 3n + 2.
- Check: n=1 → 5 ✓; n=4 → 14 ✓.
Example: 20, 17, 14, 11, ...
- Difference = −3 → coefficient is −3.
- −3n gives −3, −6, −9, −12, ...
- Difference from sequence: 20−(−3)=23.
- nth term = −3n + 23 (or 23 − 3n).
Finding a specific term
Substitute n into the nth term formula.
Example: nth term = 4n − 1. Find the 20th term: 4(20) − 1 = 79.
Is a value in the sequence?
Set the nth term equal to the value and solve. If n is a positive integer, it's in the sequence.
Example: Is 97 in the sequence 3n + 2? 3n + 2 = 97 → 3n = 95 → n = 31.67... → NOT an integer → 97 is not in the sequence.
Quadratic sequences
A quadratic sequence has a constant second difference.
nth term = an² + bn + c.
Method:
- Find first differences, then second differences.
- a = (second difference) ÷ 2.
- Form an², subtract from the sequence to get a linear remainder.
- Find the nth term of the remainder (linear method above).
Example: 3, 10, 21, 36, 55, ...
- 1st differences: 7, 11, 15, 19 (increasing by 4).
- 2nd differences: 4, 4, 4 → constant → quadratic confirmed.
- a = 4 ÷ 2 = 2.
- Subtract 2n² from sequence: 3−2=1, 10−8=2, 21−18=3, 36−32=4, 55−50=5 → sequence 1,2,3,4,5 → linear nth term = n.
- Full nth term = 2n² + n.
- Check: n=1 → 2+1=3 ✓; n=3 → 18+3=21 ✓.
Common OCR exam mistakes
- Confusing the nth term with the "difference" — the nth term is a FORMULA, not just the difference.
- Not checking the answer by substituting n=1 and n=2 (at minimum).
- Quadratic: dividing the FIRST difference by 2 instead of the SECOND difference by 2.
- Finding which term has a given value: forgetting to check n is a positive integer.
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