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GCSE/Mathematics/OCR

A9Plot linear graphs; y = mx + c; parallel and perpendicular lines

Notes

Linear graphs and y = mx + c

Linear graphs underpin half of OCR J560 algebra. Every paper has at least one question on plotting, gradient, intercepts, or parallel/perpendicular lines.

The form y = mx + c

Every non-vertical straight line can be written as y = mx + c where:

  • m = gradient (slope) = how much y changes per unit increase in x.
  • c = y-intercept = y-value when x = 0.

Plotting a linear graph

Method 1 — table of values:

  • Pick three or more x values (include negatives and zero).
  • Compute y = mx + c for each.
  • Plot the points and join with a straight line, extended.

Method 2 — gradient and intercept:

  • Mark (0, c) on the y-axis.
  • From there, go right 1 and up m (or down |m| if m < 0).
  • Plot a second point and draw the line.

Calculating gradient from two points

Given (x₁, y₁) and (x₂, y₂):

m = (y₂ − y₁) / (x₂ − x₁)

"Rise over run."

Example: from (1, 3) to (4, 9). m = (9 − 3)/(4 − 1) = 6/3 = 2.

Special lines

EquationType
y = chorizontal (gradient 0)
x = avertical (undefined gradient)
y = xgradient 1, through origin
y = −xgradient −1, through origin

Parallel lines

Two lines are parallel ⟺ they have the same gradient.

If y = 3x + 2 is parallel to y = mx + c, then m = 3 (any c).

Perpendicular lines (Higher)

Two lines are perpendicular ⟺ the product of their gradients is −1.

If a line has gradient m, the perpendicular has gradient −1/m (the negative reciprocal).

Example: perpendicular to y = 2x + 1 has gradient −1/2.

Finding the equation of a line

Given gradient m and a point (x₀, y₀):

  • y − y₀ = m(x − x₀), then rearrange to y = mx + c.

Given two points: find m first, then use either point.

OCR mark scheme conventions

  • B1 for the gradient.
  • B1 for the y-intercept.
  • A1 for the equation in the requested form.
  • For graph plots: B1 for accurate plotting (within tolerance), B1 for ruled line through plotted points.

Common mistakes

  1. Confusing the gradient formula — putting Δx on top.
  2. Forgetting the negative sign in negative gradients.
  3. For perpendicular: writing 1/m instead of −1/m.
  4. Plotting (m, c) instead of (0, c).

AI-generated · claude-opus-4-7 · v3-ocr-maths-leaves

Practice questions

Try each before peeking at the worked solution.

  1. Question 14 marks

    Plot and read off

    OCR J560/01 — Foundation (non-calculator)

    Consider the line y = 2x − 3.

    (a) Complete a table of values for x = −1, 0, 1, 2, 3. [2]
    (b) State the y-intercept of the line. [1]
    (c) State the gradient. [1]

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    AI-generated · claude-opus-4-7 · v3-ocr-maths-leaves

  2. Question 25 marks

    Equation from two points

    OCR J560/02 — Foundation (calculator)

    A line passes through (1, 5) and (4, 14).

    (a) Find the gradient of the line. [2]
    (b) Find the equation of the line in the form y = mx + c. [3]

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    AI-generated · claude-opus-4-7 · v3-ocr-maths-leaves

  3. Question 35 marks

    Parallel and perpendicular

    OCR J560/05 — Higher (calculator)

    A line L has equation y = 4x − 7.

    (a) State the equation of any line parallel to L that passes through (0, 5). [1]
    (b) Find the equation of the line perpendicular to L passing through (8, 3). [4]

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    AI-generated · claude-opus-4-7 · v3-ocr-maths-leaves

Flashcards

A9 — Plot linear graphs; y = mx + c; parallel and perpendicular lines

7-card SR deck for OCR GCSE Mathematics J560 (leaf top-up — batch 2) topic A9

7 cards · spaced repetition (SM-2)